numpy.isfinite() in Python (original) (raw)

Last Updated : 08 Mar, 2024

The numpy.isfinite() function tests element-wise whether it is finite or not(not infinity or not Not a Number) and return the result as a boolean array. Syntax :

numpy.isfinite(array [, out])

Parameters :

array : [array_like]Input array or object whose elements, we need to test for infinity out : [ndarray, optional]Output array placed with result. Its type is preserved and it must be of the right shape to hold the output.

Return :

boolean array containing the result

Code 1 :

Python

import numpy as geek

print ( "Finite : " , geek.isfinite( 1 ), "\n" )

print ( "Finite : " , geek.isfinite( 0 ), "\n" )

print ( "Finite : " , geek.isfinite(geek.nan), "\n" )

print ( "Finite : " , geek.isfinite(geek.inf), "\n" )

print ( "Finite : " , geek.isfinite(geek.NINF), "\n" )

Output :

Finite : True

Finite : False

Code 2 :

Python

import numpy as geek

b = geek.arange( 20 ).reshape( 5 , 4 )

print ( "\n" ,b)

print ( "\nIs Finite : \n" , geek.isfinite(b))

b = [[ 1j ],

`` [geek.inf]]

print ( "\nIs Finite : \n" , geek.isfinite(b))

Output :

[[ 0 1 2 3] [ 4 5 6 7] [ 8 9 10 11] [12 13 14 15] [16 17 18 19]]

Is Finite : [[ True True True True] [ True True True True] [ True True True True] [ True True True True] [ True True True True]]

Is Finite : [[ True] [False]]

Note : These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.