numpy.isfortran() in Python (original) (raw)

Last Updated : 29 Nov, 2018

numpy.isfortran(array) : This is a logical function that checks whether array is Fortran contiguous or not.

Order : [C-contiguous, F-contiguous, A-contiguous; optional]

C-contiguous order in memory(last index varies the fastest). C order means that operating row-rise on the array will be slightly quicker.
FORTRAN-contiguous order in memory (first index varies the fastest). F order means that column-wise operations will be faster.
‘A’ means to read / write the elements in Fortran-like index order if, array is Fortran contiguous in memory, C-like order otherwise.

Parameters :

array : [array_like]Input array

Return :

True, if array is Fortran; else False

Code 1 :

import numpy as np

in_array = np.array([[ 1 , 2 , 3 ], [ 4 , 5 , 6 ]], order = 'C' )

print ( "Input array : \n" , in_array)

exp2_values = np.exp2(in_array)

print ( "\nisfortran : " , np.isfortran(in_array))

Output :

Input array : [[1 2 3] [4 5 6]]

isfortran : False

Code 2 :

import numpy as np

in_array = np.array([[ 1 , 2 , 3 ], [ 4 , 5 , 6 ]], order = 'F' )

print ( "Input array : \n" , in_array)

exp2_values = np.exp2(in_array)

print ( "\nisfortran : " , np.isfortran(in_array))

Output :

Input array : [[1 2 3] [4 5 6]]

isfortran : True

References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.isfortran.html#numpy.isfortran
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