numpy.isinf() in Python (original) (raw)

Last Updated : 08 Mar, 2024

The numpy.isinf() function tests element-wise whether it is +ve or -ve infinity or not return the result as a boolean array.

Syntax: numpy.isinf(array [, out])

Parameters :

array : [array_like]Input array or object whose elements, we need to test for infinity out : [ndarray, optional]Output array placed with result. Its type is preserved and it must be of the right shape to hold the output.

Return :

boolean array containing the result. For scalar input, the result is a new boolean with value True if the input is positive or negative infinity; otherwise the value is False. For array input, the result is a boolean array with the same shape as the input and the values are True where the corresponding element of the input is positive or negative infinity; elsewhere the values are False.

Code 1 :

Python

import numpy as geek

print ( "Finite : " , geek.isinf( 1 ), "\n" )

print ( "Finite : " , geek.isinf( 0 ), "\n" )

print ( "Finite : " , geek.isinf(geek.nan), "\n" )

print ( "Finite : " , geek.isinf(geek.inf), "\n" )

print ( "Finite : " , geek.isinf(geek.NINF), "\n" )

x = geek.array([ - geek.inf, 0. , geek.inf])

y = geek.array([ 2 , 2 , 2 ])

print ( "Checking for infinity : " , geek.isinf(x, y))

Output :

Finite : False

Finite : True

Checking for infinity : [1 0 1]

Code 2 :

Python

import numpy as geek

b = geek.arange( 8 ).reshape( 2 , 4 )

print ( "\n" ,b)

print ( "\nIs Infinity : \n" , geek.isinf(b))

b = [[geek.inf],

`` [geek.NINF]]

print ( "\nIs Infinity : \n" , geek.isinf(b))

Output :

[[0 1 2 3] [4 5 6 7]]

Is Infinity : [[False False False False] [False False False False]]

Is Infinity : [[ True] [ True]]

Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.