numpy.isneginf() in Python (original) (raw)
Last Updated : 08 Mar, 2024
The numpy.isneginf() function tests element-wise whether it is negative infinity or not, and returns the result as a boolean array.
Syntax :
numpy.isneginf(array, y = None)
Parameters :
array : [array_like]Input array or object whose elements, we need to test for infinity. y : [array_like]A boolean array with the same shape and type as x to store the result.
Return :
boolean array containing the result. For scalar input, the result is a new boolean with value True if the input is positive or negative infinity; otherwise the value is False. For array input, the result is a boolean array with the same shape as the input and the values are True where the corresponding element of the input is positive or negative infinity; elsewhere the values are False.
Code 1 :
Python
import
numpy as geek
print
(
"Negative : "
, geek.isneginf(
1
),
"\n"
)
print
(
"Negative : "
, geek.isneginf(
0
),
"\n"
)
print
(
"Negative : "
, geek.isneginf(geek.nan),
"\n"
)
print
(
"Negative : "
, geek.isneginf(geek.inf),
"\n"
)
print
(
"Negative : "
, geek.isneginf(geek.NINF),
"\n"
)
x
=
geek.array([
-
geek.inf,
0.
, geek.inf])
y
=
geek.array([
2
,
2
,
2
])
print
(
"Checking for negativity : "
, geek.isneginf(x, y))
Output :
Negative : False
Negative : False
Negative : False
Negative : False
Negative : True
Checking for negativity : [1 0 0]
Code 2 :
Python
import
numpy as geek
b
=
geek.arange(
18
).reshape(
3
,
6
)
print
(
"\n"
,b)
print
(
"\nIs Negative Infinity : \n"
, geek.isneginf(b))
b
=
[[geek.inf],
`` [geek.NINF]]
print
(
"\nIs Negative Infinity : \n"
, geek.isneginf(b))
Output :
[[ 0 1 2 3 4 5] [ 6 7 8 9 10 11] [12 13 14 15 16 17]]
Is Negative Infinity : [[False False False False False False] [False False False False False False] [False False False False False False]]
Is Negative Infinity : [[False] [ True]]
Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
.