numpy.isposinf() in Python (original) (raw)

Last Updated : 08 Mar, 2024

The numpy.isposinf() function tests element-wise whether it is positive infinity or not and returns the result as a boolean array.

Syntax :

numpy.isposinf(array, y = None)

Parameters:

array : [array_like]Input array or object whose elements, we need to test for infinity. y : [array_like]A boolean array with the same shape and type as x to store the result.

Return:

boolean array containing the result. For scalar input, the result is a new boolean with value True if the input is positive or negative infinity; otherwise the value is False. For array input, the result is a boolean array with the same shape as the input and the values are True where the corresponding element of the input is positive or negative infinity; elsewhere the values are False.

Code 1:

Python

import numpy as geek

print ( "Positive : " , geek.isposinf( 1 ), "\n" )

print ( "Positive : " , geek.isposinf( 0 ), "\n" )

print ( "Positive : " , geek.isposinf(geek.nan), "\n" )

print ( "Positive : " , geek.isposinf(geek.inf), "\n" )

print ( "Positive : " , geek.isposinf(geek.NINF), "\n" )

x = geek.array([ - geek.inf, 0. , geek.inf])

y = geek.array([ 2 , 2 , 2 ])

print ( "Checking for positivity : " , geek.isposinf(x, y))

Output :

Positive : False

Positive : True

Positive : False

Checking for positivity : [0 0 1]

Code 2 :

Python

import numpy as geek

b = geek.arange( 18 ).reshape( 3 , 6 )

print ( "\n" ,b)

print ( "\nIs Positive Infinity : \n" , geek.isposinf(b))

b = [[geek.inf],

`` [geek.NINF]]

print ( "\nIs Positive Infinity : \n" , geek.isposinf(b))

Output :

[[ 0 1 2 3 4 5] [ 6 7 8 9 10 11] [12 13 14 15 16 17]]

Is Positive Infinity : [[False False False False False False] [False False False False False False] [False False False False False False]]

Is Positive Infinity : [[ True] [False]]

Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.