numpy.less() in Python (original) (raw)

Last Updated : 08 Mar, 2024

The numpy.less() : checks whether x1 is lesser than x2 or not. Syntax :

numpy.less(x1, x2[, out])

Parameters :

x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be broadcastable to a common shape out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.

Return :

Boolean array indicating results, whether x1 is lesser than x2 or not.

Code 1 :

Python

import numpy as geek

a = geek.less([ 8. , 2. ], [ 5. , 3. ])

print ( "Not equal : \n" , a, "\n" )

b = geek.less([ 2 , 2 ], [[ 1 , 3 ],[ 1 , 4 ]])

print ( "Not equal : \n" , b, "\n" )

a = geek.array([ 4 , 2 ])

b = geek.array([ 6 , 2 ])

print ( "Is a lesser than b : " , a < b)

Output :

Not equal : [False True]

Not equal : [[False True] [False True]]

Is a lesser than b : [ True False]]

Code 2 :

Python

import numpy as geek

a = geek.array([ 1j , 2 ])

b = geek.array([ 1 , 2 ])

print ( "Comparing complex with int : " , a < b)

d = geek.less(a, b)

print ( "\n Comparing complex with int .less() : " , d)

Output :

Comparing complex with int : [ True False]

Comparing complex with int .less() : [ True False]

Code 3 :

Python

import numpy as geek

a = geek.array([ 1.1 , 1 ])

b = geek.array([ 1 , 2 ])

print ( "Comparing float with int : " , a < b)

d = geek.less(a, b)

print ( "\n Comparing float with int using .less() : " , d)

Output :

Comparing float with int : [False True]

Comparing float with int using .less() : [False True]