numpy.ma.ediff1d() function in Python (original) (raw)

Last Updated : 12 Nov, 2020

numpy.ma.ediff1d() function return the differences between consecutive elements of an array.

Syntax : numpy.ma.ediff1d(arr, to_end = None, to_begin = None)

Parameters :
arr : [array_like] Input array.
to_end : [array_like, optional] Number to append at the end of the returned differences.
to_begin : [array_like, optional] Number to prepend at the beginning of the returned differences.

Return : Return the differences between consecutive elements of an array.

Code #1:

Python3

import numpy as geek

arr = geek.array([ 3 , 5 , 8 , 4 , 12 ])

gfg = geek.ma.ediff1d(arr)

print (gfg)

Output:

[ 2 3 -4 8]

Code #2:

Python3

import numpy as geek

arr = geek.array([ 3 , 5 , 8 , 4 , 12 ])

gfg = geek.ma.ediff1d(arr, to_begin = geek.array([ - 23 , 0 ]), to_end = 25 )

print (gfg)

Output:

[-23 0 2 3 -4 8 25]

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