numpy.ma.is_mask() function | Python (original) (raw)
Last Updated : 05 May, 2020
numpy.ma.is_mask()
function return True if parameter m is a valid, standard mask. This function does not check the contents of the input, only that the type is MaskType. In particular, this function returns False if the mask has a flexible dtype.
Syntax : numpy.ma.is_mask(m)
Parameter :
m : [array_like] Array to check.
Return : [bool] True if m.dtype.type is MaskType, False otherwise.
Code #1 :
import
numpy as geek
import
numpy.ma as ma
m
=
ma.masked_equal([
0
,
1
,
2
,
0
,
3
],
0
)
gfg
=
ma.is_mask(m)
print
(gfg)
Output :
False
Code #2 :
import
numpy as geek
import
numpy.ma as ma
m
=
[
True
,
False
,
True
]
gfg
=
ma.is_mask(m)
print
(gfg)
Output :
False
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