numpy.tile() in Python (original) (raw)
Last Updated : 28 Mar, 2022
The numpy.tile() function constructs a new array by repeating array – ‘arr’, the number of times we want to repeat as per repetitions. The resulted array will have dimensions max(arr.ndim, repetitions) where, repetitions is the length of repetitions. If arr.ndim > repetitions, reps is promoted to arr.ndim by pre-pending 1’s to it. If arr.ndim < repetitions, reps is promoted to arr.ndim by pre-pending new axis. Syntax :
numpy.tile(arr, repetitions)
Parameters :
array : [array_like]Input array. repetitions : No. of repetitions of arr along each axis.
Return :
An array with repetitions of array - arr as per d, number of times we want to repeat arr
Code 1 :
Python
import
numpy as geek
arr
=
geek.arange(
5
)
print
("arr : \n", arr)
repetitions
=
2
print
("Repeating arr
2
times : \n", geek.tile(arr, repetitions))
repetitions
=
3
print
("\nRepeating arr
3
times : \n", geek.tile(arr, repetitions))
Output :
arr : [0 1 2 3 4] Repeating arr 2 times : [0 1 2 3 4 0 1 2 3 4]
Repeating arr 3 times : [0 1 2 ..., 2 3 4]
Code 2 :
Python
import
numpy as geek
arr
=
geek.arange(
3
)
print
("arr : \n", arr)
a
=
2
b
=
2
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
a
=
3
b
=
2
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
a
=
2
b
=
3
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
Output :
arr : [0 1 2]
Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (2, 6)
Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (3, 6)
Repeating arr : [[0 1 2 ..., 0 1 2] [0 1 2 ..., 0 1 2]] arr Shape : (2, 9)
Code 3 : (repetitions == arr.ndim) == 0
Python
import
numpy as geek
arr
=
geek.arange(
4
).reshape(
2
,
2
)
print
("arr : \n", arr)
a
=
2
b
=
1
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
a
=
3
b
=
2
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
a
=
2
b
=
3
repetitions
=
(a, b)
print
("\nRepeating arr : \n", geek.tile(arr, repetitions))
print
("arr Shape : \n", geek.tile(arr, repetitions).shape)
Output :
arr : [[0 1] [2 3]]
Repeating arr : [[0 1] [2 3] [0 1] [2 3]] arr Shape : (4, 2)
Repeating arr : [[0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3]] arr Shape : (6, 4)
Repeating arr : [[0 1 0 1 0 1] [2 3 2 3 2 3] [0 1 0 1 0 1] [2 3 2 3 2 3]] arr Shape : (4, 6)
References : https://docs.scipy.org/doc/numpy/reference/generated/numpy.tile.html Note : These codes won’t run on online IDE’s. Please run them on your systems to explore the working .