Electric Field Lines (original) (raw)

Last Updated : 26 May, 2026

Electric field lines are a representation used to visualize the electric field surrounding charged objects.

Direction of Electric Field Lines

The concept of an electric field line is used to define an electric field near charged particles. They were first used by Michael Faraday to define an electric field due to an electron and a proton. They are also called electric lines of force.

EF-lines

They are regular lines without any breaks and are curved in nature. In the case of a positive charge, the direction of the electric field lines is radially outwards, and in the case of a negative charge, the direction of the electric field lines is radially inwards. Also, the density of the electric field lines shows the strength of the electric field, i.e., the more electric field lines in an area, the stronger the electric field there.

Properties

Rules for Drawing Electric Field Lines

The rules used for drawing electric field lines are discussed below:

Electric Field Lines for Different Charges

Using the above rules, we can draw electric field lines for different configurations of electric charges.

Electric Field Lines for Individual Charges

In the case of an individual positive charge, the direction of the electric field line is radially outwards, and in the case of an individual negative charge, the direction of the electric field line is radially inwards.

Electric Field Lines for Two Equal and Unlike Charges

For two equal and unlike charges, the electric field will originate from the positive charge and enter into the negative charge, forming a closed loop.

Electric Field Lines for Two Equal and Like Charges

In the case of two equal and like charges, both will exert a repulsive force on each other, and the arrangement of electric field lines will be on either side of each charge.

Solved Problems

**Example 1: At any time, a force of 10 N is operating on the charge of 18 μC. Determine the intensity of the electric field at that location.

**Solution: Given:
F = 10 N, q = 18 μC

**E = F/q
E = 10 / 18 × 10-6
E = 5.5 × 105 N/C

**Example 2: Calculate the strength of the electric field at a distance of 12 cm with a voltage of 68 V.

**Solution: Given:
V = 68 V, r = 12 cm

E = V/r

E = 68/12
E = 5.66 V/cm

**Example 3: A force of 12 N is acting on the charge of 27 μC. Find Electric Field.

**Solution: Given:
F = 12 N, q = 27 μC

**E = F/q

E = 12 / 27 × 10-6
E = 4.44 × 105 N/C

**Example 4: If The electric field is 6.4 N/C at a distance of 6 cm, then find the voltage.

**Solution: Given:
E = 6.4 N/C, r = 6 cm

**V = E × r

V = 6.4 ×6
V = 38.4 V