Electrical Energy and Power (original) (raw)

Last Updated : 3 Jun, 2026

Electric energy, produced by the movement of charged particles, is one of the most essential forms of energy used in electrical devices. Each device has a power rating in watts indicating its energy consumption, with high-power devices like air conditioners and refrigerators having higher ratings. When current flows through a conductor from point A to B, the electric potential decreases from V(A) to V(B), converting electrical potential energy into useful forms such as light or heat.

V = V(A) - V(B)

V > 0

In time "t", the charge Q travels from point A to point B.

Electrical Energy of a cell

Formula of Electrical Energy

Let's say the potential energy at point A is denoted by UA, while the potential energy at point B is denoted by UB.

Potential Energy at points:

UA = Q × VA

UB = Q × VB

Let the change in potential energy be denoted by Unet

Unet = Final Potential Energy - Initial Potential Energy

Unet = UB - UA

Unet = Q × VB - Q × VA

Unet = - ∆Q.V (Now, I = ∆Q/∆t)

Unet = - I × ∆ t × V

If charges moved freely inside the conductor, the loss in potential energy would convert entirely into kinetic energy, keeping total energy conserved.

∆K = -∆U

In real conductors, electrons collide with ions and move slowly (drift velocity). Due to this, energy is lost as heat in the conductor.
The work done is:

∆ W = I × V × ∆ t

Units

Commercial Unit

The commercial unit for measuring Electrical Energy is the kilowatt-hour (kWh), which is also known as the Board of Trade Unit (B.O.T.).

transformer

The image shows how the electric power is transmitted.

**Note: One kWh is also called one unit

Examples

Electrical Energy Into Mechanical Energy

Electrical energy can easily be converted into mechanical energy using Faraday's law of electromagnetism.

An electric motor is the best device that converts electrical energy into mechanical energy.

Electric Power

Power is the rate of doing work. In an electric circuit, it represents the energy converted into heat when current flows through a conductor. This heat produced in electrical appliances due to resistance is called power loss or ohmic loss.

Rewriting the previous equation,

P = ∆W / t

P = I × V

Using ohm's law relation V = IR for substituting the values inside the above equation,

P = I × V

P = I × I × R

P = I2R

It can also be written as,

P = I × V

P = (V/R) × V

P = V2/R

Thus, the power dissipated in a conductor can be written as,

P = V \times I

P = \frac{V^2}{R}

P = \frac {I^2}{R}

where,

Rating of Electrical Appliances

Every electrical appliance carries a power rating.

For example:

Power rating indicates electrical power consumed at rated voltage.

Meaning of Power Rating

Suppose a bulb is rated:

100W, 220V

This means:

Electrical Energy vs Electric Power

Factors Electrical Energy Electric Power
Definition The capacity of an electric circuit to do work is called electric energy. The rate of electric energy per unit of time is called Electric power.
Symbol It is represented by the symbol ‘W’ It is represented by the symbol ‘P’
Formula The formula for electric energy is W = Work × Time The formula for electric power is P = Work/Time
Unit The S.I unit for measuring Electrical Energy is the joule (J) or watt-second (Ws).The commercial unit of Electrical Energy is Kilowatt-hours (kWh). The S.I unit for measuring Electric Power is Watt (W) or Joule/Sec (J/s)
Storage Medium Electrical energy can easily be stored in various devices. E.g., batteries, cells, capacitors, and others Power cannot be stored in any device.

Solved Problems

**Example 1: Find the power dissipated in a conductor with a 10V potential difference and a current of 5A.

**Solution: P = VI

Given,

V = 10
I = 5

P = VI

P = (10)(5)

P = 50 W

The power dissipated is 50 W

**Example 2: Determine the power dissipated in a conductor with a 5V potential difference and a current of 2A.

**Solution: P = VI

Given

V = 5
I = 2

P = VI

P = (5)(2)

P = 10 W

The power dissipated is 10 W

**Example 3: An electric heater is connected to a battery with a 5V potential difference. The heater has a total resistance of 50 ohms. Find the power dissipated by the electric heater.

**Solution: P = V2/R

Given,

V = 5
R = 50

P = (52)/(50)

P = 0.5 W

The power dissipated is 0.5 W

**Example 4: An electric fan is connected to a battery with a potential difference of 20 volts. Assume that the fan has a total resistance of 15 ohms. Find the power dissipated by the electric fan.

**Solution: P = V2/R

Given,

V = 20
R = 15

P = V2/R

P = (202)/(15)

P = 400/15

P = 26.67 W

The power dissipated is 26.67 W

**Example 5: An electrical appliance is connected to a battery, due to which a current of 5A flows through it. The appliance has a total resistance of 10 ohms. Find the power dissipated by the appliance.

**Solution: P = I2R

Given:

I = 5
R = 10

P = (52)(10)

P = (25)(10)

P = 250 W

The power dissipated is 250 W

**Example 6: An electrical appliance is connected to a battery, due to which a current of 10A flows through it. The appliance has a total resistance of 20 ohms. Find the power dissipated by the appliance.

**Solution: P = I2R

Given,

I = 10
R = 20

P = (102)(20)

P = (100)(20)

P = 2000 W

The power dissipated is 2000 W

Unsolved Problems

**Question 1: A resistor of 25 Ω is connected to a 100 V power supply. Find the electrical energy consumed in 10 minutes.

**Question 2: An electric iron draws a current of 3 A when connected to a 220 V supply. Calculate the power consumed and the energy used in 5 minutes.

**Question 3: A device works on a 12 V battery and consumes 1800 J of energy. Find the current drawn if it operates for 5 minutes.

**Question 4: Two resistors of 10 Ω and 20 Ω are connected in series to a 120 V supply. Calculate the total power consumed and energy dissipated in 15 minutes.

**Question 5: An electric heater is connected to a 220 V supply and consumes 2 kWh of energy in 1 hour. Find the resistance of the heater.