Thermal Conductivity (original) (raw)

Last Updated : 10 Jun, 2026

Thermal conductivity is the property of a material that measures its ability to conduct heat.

file

Fourier’s Law of Heat Conduction

\frac{Q}{t} = kA \frac{\Delta T}{L}

where,

file

Thermal Conductivity Measurement

Thermal conductivity is measured by determining the rate of heat flow through a material under a known temperature difference. A temperature gradient is applied, and heat flow is recorded to calculate its value.

Common methods include the Guarded Hot Plate method and the Heat Flow Meter method, which require proper calibration for accurate results. This measurement is important in selecting materials for construction, electronics, and thermal management systems.

**Steady-State Techniques of Thermal Conductivity

Transient Techniques of Thermal Conductivity

Transient techniques are methods used to measure thermal conductivity when the system is not in steady state. In these methods, the temperature of the material changes continuously with time after a sudden heat input is given. The heat flow is not constant, and the temperature response is used to study how heat spreads through the material.

Effect of Temperature on Thermal Conductivity in Metals

Effect of Temperature on Thermal Conductivity in Non-Metals

**Factors Affecting Thermal Conductivity

Thermal conductivity of a material depends on its internal structure and external conditions. It varies because different materials have different abilities to transfer heat through particles like electrons and lattice vibrations.

Solved Problems

**Question 1: A slab has thermal conductivity k = 200 W/(m⋅K), area A = 2 m, thickness L = 0.5 m, and temperature difference ΔT = 20 K. Find the rate of heat flow.

**Solution: Formula:

\frac{Q}{t} = kA \frac{\Delta T}{L}

\frac{Q}{t} = 200 \times 2 \times \frac{20}{0.5}

\frac{Q}{t} = 16000 \, W

**Question 2: A material has k = 50 W/(m⋅K), A = 1 m, L = 0.2m, ΔT = 10 K. Find heat flow rate.

**Solution: Formula:

\frac{Q}{t} = kA \frac{\Delta T}{L}

\frac{Q}{t} = 50 \times 1 \times \frac{10}{0.2}

\frac{Q}{t} = 2500 \, W

**Question 3: Find thermal conductivity if heat flow rate is 100 W, area = 1 m², thickness = 0.5 m, and temperature difference = 20 K.

**Solution: Formula:

k = \frac{Q L}{A t \Delta T}

k = \frac{100 \times 0.5}{1 \times 20}

k = 2.5 \, W/(m \cdot K)

**Question 4: A slab has k = 10 W/(m⋅K), A = 3 m 2 , L = 0.3 m, and ΔT = 30 K. Find heat flow rate.

**Solution: Formula:

\frac{Q}{t} = kA \frac{\Delta T}{L}

\frac{Q}{t} = 10 \times 3 \times \frac{30}{0.3}

\frac{Q}{t} = 3000 \, W

Unsolved Problems

**Question 1: A slab has thermal conductivity k = 150 W/m⋅K, area A = 3 m, thickness L = 0.6m, and temperature difference ΔT = 30 K. Find the rate of heat flow.

**Question 2: A material of area 2 m 2 and thickness 0.4m conducts heat at a rate of 4000 W when the temperature difference is 20 K. Find its thermal conductivity.

**Question 3: A wall has thermal conductivity k = 0.8 W/m⋅K. If heat flow rate is 160W, area is 4m 2 , and thickness is 0.5m, find the temperature difference across the wall.

**Question 4: A slab of thickness 0.25m and area 1.5 m has thermal conductivity 50 W/m⋅K. If the temperature difference is 40K, find the heat flow rate.