Python Program to Find closest number in array (original) (raw)

Last Updated : 17 Apr, 2023

Given an array of sorted integers. We need to find the closest value to the given number. Array may contain duplicate values and negative numbers.

Examples:

Input : arr[] = {1, 2, 4, 5, 6, 6, 8, 9} Target number = 11 Output : 9 9 is closest to 11 in given array

Input :arr[] = {2, 5, 6, 7, 8, 8, 9}; Target number = 4 Output : 5

A simple solution is to traverse through the given array and keep track of absolute difference of current element with every element. Finally return the element that has minimum absolution difference.

Method #1: Using Binary search

Python3 `

Python3 program to find element

closest to given target.

Returns element closest to target in arr[]

def findClosest(arr, n, target):

# Corner cases
if (target <= arr[0]):
    return arr[0]
if (target >= arr[n - 1]):
    return arr[n - 1]

# Doing binary search
i = 0
j = n
mid = 0
while (i < j):
    mid = (i + j) // 2

    if (arr[mid] == target):
        return arr[mid]

    # If target is less than array
    # element, then search in left
    if (target < arr[mid]):

        # If target is greater than previous
        # to mid, return closest of two
        if (mid > 0 and target > arr[mid - 1]):
            return getClosest(arr[mid - 1], arr[mid], target)

        # Repeat for left half
        j = mid

    # If target is greater than mid
    else:
        if (mid < n - 1 and target < arr[mid + 1]):
            return getClosest(arr[mid], arr[mid + 1], target)

        # update i
        i = mid + 1

# Only single element left after search
return arr[mid]

Method to compare which one is the more close.

We find the closest by taking the difference

between the target and both values. It assumes

that val2 is greater than val1 and target lies

between these two.

def getClosest(val1, val2, target):

if (target - val1 >= val2 - target):
    return val2
else:
    return val1

Driver code

arr = [1, 2, 4, 5, 6, 6, 8, 9] n = len(arr) target = 11 print(findClosest(arr, n, target))

`

Time Complexity: O(log(n))
Auxiliary Space: O(log(n)) (implicit stack is created due to recursion)

Method #2: Using min() function

Python3 `

Python3 program to find element

closest to given target.

def findClosestValue(givenList, target):

def difference(givenList):
    return abs(givenList - target)

result = min(givenList, key=difference)

return result

if name == "main":

givenList = [1, 2, 4, 5, 6, 6, 8, 9]

target = 11

result = findClosestValue(givenList, target)

print("The closest value to the " + str(target)+" is", result)

This code is contributed by vikkycirus

`

Output

The closest value to the 11 is 9

Method #3: Using Two Pointers

Another approach to solve this problem is to use two pointers technique, where we maintain two pointers left and right, and move them towards each other based on their absolute difference with target.

Below are the steps:

1. Initialize left = 0 and right = n-1, where n is the size of the array.
2. Loop while left < right
   • If the absolute difference between arr[left] and target is less than or equal to the absolute difference between arr[right] and target, move left pointer one step to the right, i.e. left++
   • Else, move right pointer one step to the left, i.e. right–-
3. Return arr[left], which will be the element closest to the target.

Below is the implementation of the above approach:

Python3 `

Python program to find element

closest to given target using two pointers

import sys

def findClosest(arr, n, target): left, right = 0, n - 1 while left < right: if abs(arr[left] - target) <= abs(arr[right] - target): right -= 1 else: left += 1 return arr[left]

if name == "main": arr = [1, 2, 4, 5, 6, 6, 8, 8, 9] n = len(arr) target = 11 print(findClosest(arr, n, target))

This code is contributed by Susobhan Akhuli

`

Time Complexity: O(N), where n is the length of the array.
Auxiliary Space: O(1)

Please refer complete article on Find closest number in array for more details!