Python String concatenation in Heterogeneous list (original) (raw)

Last Updated : 13 Apr, 2023

Sometimes, while working with Python, we can come across a problem in which we require to find the concatenation of strings. This problem is easier to solve. But this can get complex cases we have a mixture of data types to go along with it. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop + conditions
We can employ a brute force method to type caste check each element, if it's a string we concatenate it. This can ensure that only strings are concatenated and hence can solve the problem.

Python3 `

Python3 code to demonstrate working of

String concatenation in Heterogeneous list

using loop + conditions

initializing list

test_list = [5, 6, "gfg ", 8, (5, 7), ' is', 9, ' best']

printing original list

print("The original list is : " + str(test_list))

String concatenation in Heterogeneous list

using loop + conditions

res = '' for ele in test_list: if type(ele) == str: res += ele

printing result

print("Concatenation of strings in list : " + str(res))

`

Output

The original list is : [5, 6, 'gfg ', 8, (5, 7), ' is', 9, ' best'] Concatenation of strings in list : gfg is best

Time Complexity: O(n*n) where n is the number of elements in the string list. The loop + conditions is used to perform the task and it takes O(n*n) time.
Auxiliary Space: O(n) additional space of size n is created where n is the number of elements in the string list.

Method #2 : Using join() + isinstance()
This problem can also be solved using the inbuilt function of join() and it also supports the instance filter using isinstance() which can be fed with strings and hence solve the problem.

Python3 `

Python3 code to demonstrate working of

String concatenation in Heterogeneous list

using join() + isinstance()

initializing list

test_list = [5, 6, "gfg ", 8, (5, 7), ' is', 9, ' best']

printing original list

print("The original list is : " + str(test_list))

String concatenation in Heterogeneous list

using join() + isinstance()

res = "".join(filter(lambda i: isinstance(i, str), test_list))

printing result

print("Concatenation of strings in list : " + str(res))

`

Output

The original list is : [5, 6, 'gfg ', 8, (5, 7), ' is', 9, ' best'] Concatenation of strings in list : gfg is best

Time Complexity: O(n*n), where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n), where n is the number of elements in the list “test_list”.

Method#3: Using reduce + type
This problem can be solved using reduce and type function. We use reduce for iteration over the list and type is used to check the type of element in iteration if it is string type then add it in our result else leave it.

Python3 `

Python3 code to demonstrate working of

String concatenation in Heterogeneous list

using reduce + type

from functools import reduce

initializing list

test_list = [5, 6, "gfg ", 8, (5, 7), ' is', 9, ' best']

printing original list

print("The original list is : " + str(test_list))

String concatenation in Heterogeneous list

using reduce + type()

ans = reduce(lambda x, y: x + y if type(y) == str else x, test_list, "")

printing result

print("Concatenation of strings in list : " + ans)

`

Output

The original list is : [5, 6, 'gfg ', 8, (5, 7), ' is', 9, ' best'] Concatenation of strings in list : gfg is best

Method #4: Using list comprehension

Step-by-step approach:

Below is the implementation of the above approach:

Python3 `

Python3 code to demonstrate working of

String concatenation in Heterogeneous list

using list comprehension

initializing list

test_list = [5, 6, "gfg ", 8, (5, 7), ' is', 9, ' best']

printing original list

print("The original list is : " + str(test_list))

String concatenation in Heterogeneous list

using list comprehension

res = ''.join([ele for ele in test_list if isinstance(ele, str)])

printing result

print("Concatenation of strings in list : " + str(res))

`

Output

The original list is : [5, 6, 'gfg ', 8, (5, 7), ' is', 9, ' best'] Concatenation of strings in list : gfg is best

Time complexity: O(n)
Auxiliary space: O(n)