Python Extract digits from Tuple list (original) (raw)

Last Updated : 7 Nov, 2025

Given a list of tuples containing numbers of varying lengths, the task is to extract all unique digits present in those tuples.

**Examples:

**Input: list = [(15, 3), (3, 9)]
**Output: [9, 5, 3, 1]

**Input: list = [(15, 3)]
**Output: [5, 3, 1]

Using List Comprehension + Set

Python `

t = [(15, 3), (3, 9), (1, 10), (99, 2)]

temp = ''.join([str(i) for s1 in t for i in s1]) res = [int(i) for i in set(temp)] print(res)

**Explanation:

**[str(i) for s1 in t for i in s1]: Converts each number in all tuples to a string.
' ****'.join(...):** Joins all string numbers into one continuous string.
**set(temp): Removes duplicate digits.
**[int(i) for i in set(temp)]: Converts unique string digits back to integers. Python `

from itertools import chain

t = [(15, 3), (3, 9), (1, 10), (99, 2)] s = map(str, chain.from_iterable(t)) res = {d for n in s for d in n} print(res)

Output

{'0', '2', '9', '5', '3', '1'}

**Explanation:

**chain.from_iterable(t): Flattens all tuples into a single sequence.
**map(str, ...): Converts each number to a string.
****{d for n in s for d in n}:** Extracts individual digits and keeps only unique ones.

A compact method that converts the tuple list to a string, removes unwanted characters using regex, and extracts unique digits using set().

Python `

import re

t = [(15, 3), (3, 9), (1, 10), (99, 2)] s = re.sub(r'[[](), ]', '', str(t)) res = [int(i) for i in set(s)] print(res)

**Explanation:

**str(t): Converts tuple list to string.
**re.sub(r'[\[\]\(\), ]', '', str(t)): Removes brackets, commas, and spaces.
**set(s): Collects unique digit characters.
**int(i) for i in set(s): Converts them back to integers.

A simple approach that iterates through each tuple, collects all digits as strings, and uses set() to extract unique digits.

Python `

t = [(15, 3), (3, 9), (1, 10), (99, 2)]

s = '' for x in t: for y in x: s += str(y) res = list(map(int, set(s))) print(res)