Python Program for Removing ith Character from a String (original) (raw)

Last Updated : 12 Nov, 2025

Given a string and an index i, remove the character at the i-th position and return the resulting string. For Example:

**Input: "PythonProgramming", i = 6
**Output: "Pythonrogramming"

Let's explore different methods to do this task.

Using String Slicing

This method removes the i-th character by directly taking parts of the string before and after the character and joining them together. It is fast and memory-efficient.

Python `

s = "PythonProgramming" i = 6 res = s[:i] + s[i+1:] print(res)

`

**Explanation:

• **s[:i]: Extracts characters from the start up to (but not including) index i.
• **s[i+1:]: Extracts characters from index i+1 to the end.
• ****'+':** Concatenates the two slices, skipping the i-th character.

Using join() with List Comprehension

This method creates a new string by iterating over all characters and joining only those that are not at the i-th index.

Python `

s = "PythonProgramming" i = 6 res = ''.join([s[j] for j in range(len(s)) if j != i]) print(res)

`

**Explanation:

• **[s[j] for j in range(len(s)) if j != i]: Iterates through all indices and skips the i-th character.
• ****''.join(...):** Converts the list of characters back into a string.

Using replace() with Slicing

This method removes the i-th character by replacing its first occurrence with an empty string.

Python `

s = "PythonProgramming" i = 6 res = s[:i] + s[i:].replace(s[i], '', 1) print(res)

`

**Explanation: **s[:i] + s[i:].replace(s[i], '', 1): Removes the i-th character by joining the part before i with the remaining substring after deleting s[i].

Using a For Loop

The for loop iterates over each character in the string and adds it to a new string only if it is not at the i-th position.

Python `

s = "PythonProgramming" i = 6

res = '' for j in range(len(s)): if j != i: res += s[j] print(res)

`