Python Program to find minimum number of rotations to obtain actual string (original) (raw)

Last Updated : 9 Sep, 2022

Given two strings s1 and s2. The task is to find out the minimum number of string rotations for the given string s1 to obtain the actual string s2. Examples:

Input : eeksg, geeks Output: 1 Explanation: g is rotated left to obtain geeks.

Input : eksge, geeks Output: 2 Explanation : e and g are left rotated to obtain geeks.

Approach:

• Use string slicing to rotate the string.
• Perform right rotations str1=str1[1:len(str1)]+str1[0] on string to obtain the actual string.
• Perform left rotations m=m[len(m)-1]+m[:len(m)-1] on string to obtain the actual string.
• Print the minimum of left(x) and right(y) rotations.

TIME COMPLEXITY: O(n) Below is the implementation:

python3 `

def findRotations(str1, str2):

# To count left rotations 
# of string
x = 0

# To count right rotations
# of string
y = 0
m = str1

while True:
    
    # left rotating the string
    m = m[len(m)-1] + m[:len(m)-1] 
    
    # checking if rotated and 
    # actual string are equal.
    if(m == str2):
        x += 1
        break
        
    else:
        x += 1
        if x > len(str2) :
            break

while True:
    
    # right rotating the string
    str1 = str1[1:len(str1)]+str1[0] 
    
    # checking if rotated and actual
    # string are equal.
    if(str1 == str2):
        y += 1
        break
        
    else:
        y += 1
        if y > len(str2):
            break
            
if x < len(str2):
    
    # printing the minimum
    # number of rotations.
    print(min(x,y))
    
else:
    print("given strings are not of same kind")
    

Driver code

findRotations('sgeek', 'geeks')

`

The Time and Space Complexity for all the methods are the same:

Time Complexity: O(n)

Auxiliary Space: O(n)