Replace missing white spaces in a string with the least frequent character using Pandas (original) (raw)

Last Updated : 17 Apr, 2023

Let's create a program in python which will replace the white spaces
in a string with the character that occurs in the string very least
using the Pandas library.

Example 1:

String S = "akash loves gfg" here: 'g' comes: 2 times 's' comes: 2 times 'a' comes: 2 times 'h' comes: 1 time  'o' comes: 1 time  'k' comes: 1 time  'v' comes: 1 time  'e' comes: 1 time  'f' comes: 1 time  'l' comes: 1 time 

In this example, there are 7 characters with least frequency 1 so, there can be 7 valid outputs One of the possible output is given below: So, the Output String will be: "akashlloveslgfg".

Example 2:

string ="goodd noon" here: g comes: 1 time o comes: 4 times d comes: 2 times n comes: 2 times So the character with the least frequency 1 is g So here white spaces will be replaced by the character g and the output will be: "gooddgnoon"

Now, Let's see the implementation:

Python3 `

importing pandas library

import pandas as pd

taking string with white spaces

newstr1 = 'akash loves gfg'

printing the original string

print("Original String given by user:", newstr1)

converting string into

list of characters

ser = pd.Series(list(newstr1))

counting the frequency

of characters

element_freq = ser.value_counts()

printing character and their

respective frequency

print(element_freq)

current_freq = element_freq.dropna().index[-1]

function element_freq.dropna()

will Return a new Series with

missing values removed

result = "".join(ser.replace(' ', current_freq))

print(result)

`

Output:

The overall time complexity is O(n log n).

The auxiliary space complexity is O(n), where n is the length of the input string.