Vector removeIf() method in Java (original) (raw)
Last Updated : 11 Jul, 2025
The removeIf() method of Vector removes all of those elements from Vector which satisfies the condition passed as a parameter to this method. This method returns true if some element are removed from the Vector. Java 8 has an important in-built functional interface which is Predicate. Predicate, or a condition checking function, which checks the given input for a given condition and returns a boolean result for the same indicating whether the condition was met or not.Syntax:
public boolean removeIf(Predicate<? super E> filter)
Parameter: This method takes a parameter filter which represents a predicate which returns true for elements to be removed.Returns: This method returns True if predicate returns true and some elements were removed.Exception: This method throws NullPointerException if the specified filter is null. Below programs illustrate removeIf() method of Vector:Example 1: To demonstrate removeIf() method on vector which contains a set of Numbers and only the numbers which are divisible by 2 will be removed.
Java `
// Java Program Demonstrate removeIf() // method of Vector
import java.util.*;
public class GFG { public static void main(String[] args) {
// create an Vector which going to
// contains a list of Numbers
Vector<Integer> Numbers = new Vector<Integer>();
// Add Number to list
Numbers.add(22);
Numbers.add(33);
Numbers.add(55);
Numbers.add(62);
// apply removeIf() method
// to remove numbers divisible by 2
Numbers.removeIf(n -> (n % 2 == 0));
System.out.println("All Numbers not divisible by 2 are:");
// print list
for (int i : Numbers) {
System.out.println(i);
}
}}
`
Output:
All Numbers not divisible by 2 are: 33 55
Example 2: To demonstrate removeIf() method on Vector which contains set of Students Names and to remove all 4 char long name.
Java `
// Java Program Demonstrate removeIf() // method of Vector
import java.util.*;
public class GFG { public static void main(String[] args) {
// create a Vector
// containing a list of string values
Vector<String> students = new Vector<String>();
// Add Strings to list
// each string represents student name
students.add("Rama");
students.add("Mohan");
students.add("Sohan");
students.add("Rabi");
students.add("Shabbir");
// apply removeIf() method
// to remove names contains 4 chars
students.removeIf(n -> (n.length() == 4));
System.out.println("Students name do not contain 4 char are");
// print list
for (String str : students) {
System.out.println(str);
}
}}
`
Output:
Students name do not contain 4 char are Mohan Sohan Shabbir
Example 3: To demonstrate NullpointerException in removeIf() method on Vector.
Java `
// Java Program Demonstrate removeIf() // method of Vector
import java.util.*;
public class GFG { public static void main(String[] args) {
// create a Vector
// containing a list of string values
Vector<String> students = new Vector<String>();
// Add Strings to list
// each string represents student name
students.add("Rama");
students.add("Mohan");
students.add("Sohan");
students.add("Rabi");
students.add("Shabbir");
try {
// apply removeIf() method with null filter
students.removeIf(null);
}
catch (Exception e) {
System.out.println("Exception: " + e);
}
}}
`
Output:
Exception: java.lang.NullPointerException