tf.math.is_non_decreasing | TensorFlow v2.0.0 (original) (raw)
tf.math.is_non_decreasing
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Returns True if x is non-decreasing.
View aliases
Compat aliases for migration
SeeMigration guide for more details.
tf.compat.v1.debugging.is_non_decreasing, tf.compat.v1.is_non_decreasing, tf.compat.v1.math.is_non_decreasing
tf.math.is_non_decreasing(
x, name=None
)
Elements of x are compared in row-major order. The tensor [x[0],...]is non-decreasing if for every adjacent pair we have x[i] <= x[i+1]. If x has less than two elements, it is trivially non-decreasing.
See also: is_strictly_increasing
| Args | |
|---|---|
| x | Numeric Tensor. |
| name | A name for this operation (optional). Defaults to "is_non_decreasing" |
| Returns |
|---|
| Boolean Tensor, equal to True iff x is non-decreasing. |
| Raises | |
|---|---|
| TypeError | if x is not a numeric tensor. |
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Last updated 2020-10-01 UTC.