tf.math.l2_normalize | TensorFlow v2.0.0 (original) (raw)
tf.math.l2_normalize
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Normalizes along dimension axis using an L2 norm.
View aliases
Main aliases
tf.linalg.l2_normalize, tf.nn.l2_normalize
tf.math.l2_normalize(
x, axis=None, epsilon=1e-12, name=None
)
For a 1-D tensor with axis = 0, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x with more dimensions, independently normalizes each 1-D slice along dimension axis.
| Args | |
|---|---|
| x | A Tensor. |
| axis | Dimension along which to normalize. A scalar or a vector of integers. |
| epsilon | A lower bound value for the norm. Will use sqrt(epsilon) as the divisor if norm < sqrt(epsilon). |
| name | A name for this operation (optional). |
| Returns |
|---|
| A Tensor with the same shape as x. |
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Last updated 2020-10-01 UTC.