numpy.choose — NumPy v1.13 Manual (original) (raw)
numpy.
choose
(a, choices, out=None, mode='raise')[source]¶
Construct an array from an index array and a set of arrays to choose from.
First of all, if confused or uncertain, definitely look at the Examples - in its full generality, this function is less simple than it might seem from the following code description (below ndi =numpy.lib.index_tricks
):
np.choose(a,c) == np.array([c[a[I]][I] for I in ndi.ndindex(a.shape)])
.
But this omits some subtleties. Here is a fully general summary:
Given an “index” array (a) of integers and a sequence of n arrays (choices), a and each choice array are first broadcast, as necessary, to arrays of a common shape; calling these Ba and Bchoices[i], i = 0,...,n-1 we have that, necessarily, Ba.shape == Bchoices[i].shape
for each i. Then, a new array with shape Ba.shape
is created as follows:
- if
mode=raise
(the default), then, first of all, each element of_a_ (and thus Ba) must be in the range [0, n-1]; now, suppose that_i_ (in that range) is the value at the (j0, j1, ..., jm) position in Ba - then the value at the same position in the new array is the value in Bchoices[i] at that same position; - if
mode=wrap
, values in a (and thus Ba) may be any (signed) integer; modular arithmetic is used to map integers outside the range_[0, n-1]_ back into that range; and then the new array is constructed as above; - if
mode=clip
, values in a (and thus Ba) may be any (signed) integer; negative integers are mapped to 0; values greater than _n-1_are mapped to n-1; and then the new array is constructed as above.
Parameters: | a : int array This array must contain integers in [0, n-1], where n is the number of choices, unless mode=wrap or mode=clip, in which cases any integers are permissible. choices : sequence of arrays Choice arrays. a and all of the choices must be broadcastable to the same shape. If choices is itself an array (not recommended), then its outermost dimension (i.e., the one corresponding tochoices.shape[0]) is taken as defining the “sequence”. out : array, optional If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype. mode : {‘raise’ (default), ‘wrap’, ‘clip’}, optional Specifies how indices outside [0, n-1] will be treated: ‘raise’ : an exception is raised ‘wrap’ : value becomes value mod n ‘clip’ : values < 0 are mapped to 0, values > n-1 are mapped to n-1 |
---|---|
Returns: | merged_array : array The merged result. |
Raises: | ValueError: shape mismatch If a and each choice array are not all broadcastable to the same shape. |
Notes
To reduce the chance of misinterpretation, even though the following “abuse” is nominally supported, choices should neither be, nor be thought of as, a single array, i.e., the outermost sequence-like container should be either a list or a tuple.
Examples
choices = [[0, 1, 2, 3], [10, 11, 12, 13], ... [20, 21, 22, 23], [30, 31, 32, 33]] np.choose([2, 3, 1, 0], choices ... # the first element of the result will be the first element of the ... # third (2+1) "array" in choices, namely, 20; the second element ... # will be the second element of the fourth (3+1) choice array, i.e., ... # 31, etc. ... ) array([20, 31, 12, 3]) np.choose([2, 4, 1, 0], choices, mode='clip') # 4 goes to 3 (4-1) array([20, 31, 12, 3])
because there are 4 choice arrays
np.choose([2, 4, 1, 0], choices, mode='wrap') # 4 goes to (4 mod 4) array([20, 1, 12, 3])
i.e., 0
A couple examples illustrating how choose broadcasts:
a = [[1, 0, 1], [0, 1, 0], [1, 0, 1]] choices = [-10, 10] np.choose(a, choices) array([[ 10, -10, 10], [-10, 10, -10], [ 10, -10, 10]])
With thanks to Anne Archibald
a = np.array([0, 1]).reshape((2,1,1)) c1 = np.array([1, 2, 3]).reshape((1,3,1)) c2 = np.array([-1, -2, -3, -4, -5]).reshape((1,1,5)) np.choose(a, (c1, c2)) # result is 2x3x5, res[0,:,:]=c1, res[1,:,:]=c2 array([[[ 1, 1, 1, 1, 1], [ 2, 2, 2, 2, 2], [ 3, 3, 3, 3, 3]], [[-1, -2, -3, -4, -5], [-1, -2, -3, -4, -5], [-1, -2, -3, -4, -5]]])