ifftn — SciPy v1.15.3 Manual (original) (raw)

scipy.fftpack.

scipy.fftpack.ifftn(x, shape=None, axes=None, overwrite_x=False)[source]#

Return inverse multidimensional discrete Fourier transform.

The sequence can be of an arbitrary type.

The returned array contains:

y[j_1,..,j_d] = 1/p * sum[k_1=0..n_1-1, ..., k_d=0..n_d-1] x[k_1,..,k_d] * prod[i=1..d] exp(sqrt(-1)2pi/n_i * j_i * k_i)

where d = len(x.shape), n = x.shape, and p = prod[i=1..d] n_i.

For description of parameters see fftn.

See also

fftn

for detailed information.

Examples

from scipy.fftpack import fftn, ifftn import numpy as np y = (-np.arange(16), 8 - np.arange(16), np.arange(16)) np.allclose(y, ifftn(fftn(y))) True