median — SciPy v1.15.3 Manual (original) (raw)

scipy.stats.Mixture.

Mixture.median(*, method=None)[source]#

Median (50th percentil)

If a continuous random variable \(X\) has probability \(0.5\) of taking on a value less than \(m\), then \(m\) is the median. That is, the median is the value \(m\) for which:

\[P(X ≤ m) = 0.5 = P(X ≥ m)\]

Parameters:

method{None, ‘formula’, ‘icdf’}

The strategy used to evaluate the median. By default (None), the infrastructure chooses between the following options, listed in order of precedence.

• 'formula': use a formula for the median
• 'icdf': evaluate the inverse CDF of 0.5

Not all method options are available for all distributions. If the selected method is not available, a NotImplementedErrorwill be raised.

Returns:

outarray

The median

References

Examples

Instantiate a distribution with the desired parameters:

from scipy import stats X = stats.Uniform(a=0., b=10.)

Compute the median:

X.median() np.float64(5.0) X.median() == X.icdf(0.5) == X.iccdf(0.5) True