std::move_iterator::operator*,-> - cppreference.com (original) (raw)

reference operator*() const; (1) (since C++11) (constexpr since C++17)
pointer operator->() const; (2) (since C++11) (constexpr since C++17) (deprecated in C++20)

Returns an rvalue reference or pointer to the current element.

[edit] Return value

[edit] Notes

operator-> is deprecated because deferencing its result may yield an lvalue. This may lead to unintended behavior.

[edit] Example

#include #include #include #include #include   void print(auto rem, const auto& v) { for (std::cout << rem; const auto& e : v) std::cout << std::quoted(e) << ' '; std::cout << '\n'; }   int main() { std::vector<std::string> p{"alpha", "beta", "gamma", "delta"}, q; print("1) p: ", p); for (std::move_iterator it{p.begin()}, end{p.end()}; it != end; ++it) { it->push_back('!'); // calls -> string::push_back(char) q.emplace_back(*it); // *it <- overload (1) } print("2) p: ", p); print("3) q: ", q);   std::vector v{1, 2, 3}; std::move_iterator it{v.begin()}; // *it = 13; // error: using rvalue as lvalue }

Possible output:

  1. p: "alpha" "beta" "gamma" "delta"
  2. p: "" "" "" ""
  3. q: "alpha!" "beta!" "gamma!" "delta!"

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior
LWG 2106 C++11 operator* would return a danglingreference if *current yields a prvalue returns the objectin this case

[edit] See also