std::basic_string_view<CharT,Traits>::find_last_of - cppreference.com (original) (raw)

Finds the last character equal to one of characters in the given character sequence. Exact search algorithm is not specified. The search considers only the interval [​0​, pos]. If the character is not present in the interval, npos will be returned.

1. Finds the last occurence of any of the characters of v in this view, ending at position pos.

2. Equivalent to find_last_of(basic_string_view(std::addressof(ch), 1), pos).

3. Equivalent to find_last_of(basic_string_view(s, count), pos).

4. Equivalent to find_last_of(basic_string_view(s), pos).

[edit] Parameters

[edit] Return value

Position of the last occurrence of any character of the substring, or npos if no such character is found.

[edit] Complexity

O(size() * v.size()) at worst.

[edit] Example

#include   using namespace std::literals; constexpr auto N = std::string_view::npos;   static_assert( 5 == "delete"sv.find_last_of("cdef"sv) && // └────────────────────┘ N == "double"sv.find_last_of("fghi"sv) && // 0 == "else"sv.find_last_of("bcde"sv, 2 /* pos [0..2]: "els" /) && // └────────────────────────┘ N == "explicit"sv.find_last_of("abcd"sv, 4 / pos [0..4]: "expli" /) && // 3 == "extern"sv.find_last_of('e') && // └────────────────────┘ N == "false"sv.find_last_of('x') && // 0 == "inline"sv.find_last_of('i', 2 / pos [0..2]: "inl" /) && // └───────────────────────┘ N == "mutable"sv.find_last_of('a', 2 / pos [0..2]: "mut" /) && // 3 == "namespace"sv.find_last_of("cdef", 3 / pos [0..3]: "name" /, 3 / "cde" /) && // └─────────────────────────┘ N == "namespace"sv.find_last_of("cdef", 3 / pos [0..3]: "name" /, 2 / "cd" */) );   int main() {}

[edit] See also