[Python-Dev] Any reason that any()/all() do not take apredicateargument? (original) (raw)

Raymond Hettinger raymond.hettinger at verizon.net
Sun Apr 16 05:26:43 CEST 2006

[Bill Janssen]

Yeah, but you can't do more complicated expressions that way, like

any(lambda x: x[3] == "thiskey")

You're not making any sense. The sequence argument is not listed and the lambda is unnecessary. Try this instead:

 any(x[3] == 'thiskey' for x in seq)

I think it makes a lot of sense for any and all to take optional predicate function arguments.

I think you don't understand what you already have to work with in Py2.5a -- a boolean expression in a genexp should always suffice -- no separate lambda based predicate function is ever required.

Raymond

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