[Python-Dev] any support for a methodcaller HOF? (original) (raw)

Eric Nieuwland eric.nieuwland at xs4all.nl
Sat Feb 4 03:48:18 CET 2006

On 4 feb 2006, at 3:18, Nick Coghlan wrote:

All I'm suggesting is that a similarly inspired syntax is worth considering when it comes to deferred expressions:

def f(x): return x*x => f = (x*x def (x))

It's not the same, as x remains free whereas in g = [x*x for x in seq] x is bound.

Yours is

f = lambda x: x*x

and it will die by Guido hand... --eric

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