[Python-Dev] 2.5 and beyond (original) (raw)
Nick Coghlan ncoghlan at gmail.com
Sat Jul 1 10:35:02 CEST 2006
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Giovanni Bajo wrote:
Yes but:
a = [] for i in range(10): ... a.append(lambda: i) ... print [x() for x in a] [9, 9, 9, 9, 9, 9, 9, 9, 9, 9] This subtle semantic of lambda is quite confusing, and still forces people to use the "i=i" trick.
If you'd like each function instance to have a separate closure scope, then give each function a separate closure scope, instead of making them all share the same one the way you have above:
def make_f(i): ... def f(): ... return i ... return f ... a = [] for i in range(10): ... a.append(make_f(i)) ... print [x() for x in a] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
Cheers, Nick.
-- Nick Coghlan | ncoghlan at gmail.com | Brisbane, Australia
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