[Python-Dev] yield * (Re: Missing operator.call) (original) (raw)
Greg Ewing greg.ewing at canterbury.ac.nz
Sun Feb 8 02:00:47 CET 2009
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Guido van Rossum wrote:
We already have yield expressions and they mean something else...
They don't have a "*" in them, though, and I don't think the existing meaning of yield as an expression would carry over into the "yield *" variant, so there shouldn't be any conflict.
But if you think there will be a conflict, or that the similarity would be too confusing, maybe the new construct should be called something else. I'm open to suggestions.
-- Greg
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