[Python-Dev] more timely detection of unbound locals (original) (raw)
Eli Bendersky eliben at gmail.com
Mon May 9 17:01:06 CEST 2011
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I think you are making an unwarranted assumption about what is "more expected". I presume you are thinking that the expected behaviour is that foo() should:
print global x (5) assign 1 to local x print local x (1) If we implemented this change, there would be no more questions about UnboundLocalError, but instead there would be lots of questions like "why is it that globals revert to their old value after I change them in a function?".
True, but this is less confusing and follows the rules in a more straightforward way. x = 1 without a 'global x' assigns a local x, this make sense and is similar to what happens in C where an inner declaration temporarily shadows a global one.
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