pandas.Index.get_slice_bound — pandas 3.0.0.dev0+2100.gf496acffcc documentation (original) (raw)
Index.get_slice_bound(label, side)[source]#
Calculate slice bound that corresponds to given label.
Returns leftmost (one-past-the-rightmost if side=='right'
) position of given label.
Parameters:
labelobject
The label for which to calculate the slice bound.
side{‘left’, ‘right’}
if ‘left’ return leftmost position of given label. if ‘right’ return one-past-the-rightmost position of given label.
Returns:
int
Index of label.
See also
Get integer location, slice or boolean mask for requested label.
Examples
idx = pd.RangeIndex(5) idx.get_slice_bound(3, "left") 3
idx.get_slice_bound(3, "right") 4
If label
is non-unique in the index, an error will be raised.
idx_duplicate = pd.Index(["a", "b", "a", "c", "d"]) idx_duplicate.get_slice_bound("a", "left") Traceback (most recent call last): KeyError: Cannot get left slice bound for non-unique label: 'a'