pandas.Series.str.findall — pandas 2.2.3 documentation (original) (raw)

Series.str.findall(pat, flags=0)[source]#

Find all occurrences of pattern or regular expression in the Series/Index.

Equivalent to applying re.findall() to all the elements in the Series/Index.

Parameters:

patstr

Pattern or regular expression.

flagsint, default 0

Flags from re module, e.g. re.IGNORECASE (default is 0, which means no flags).

Returns:

Series/Index of lists of strings

All non-overlapping matches of pattern or regular expression in each string of this Series/Index.

See also

count

Count occurrences of pattern or regular expression in each string of the Series/Index.

extractall

For each string in the Series, extract groups from all matches of regular expression and return a DataFrame with one row for each match and one column for each group.

re.findall

The equivalent re function to all non-overlapping matches of pattern or regular expression in string, as a list of strings.

Examples

s = pd.Series(['Lion', 'Monkey', 'Rabbit'])

The search for the pattern ‘Monkey’ returns one match:

s.str.findall('Monkey') 0 [] 1 [Monkey] 2 [] dtype: object

On the other hand, the search for the pattern ‘MONKEY’ doesn’t return any match:

s.str.findall('MONKEY') 0 [] 1 [] 2 [] dtype: object

Flags can be added to the pattern or regular expression. For instance, to find the pattern ‘MONKEY’ ignoring the case:

import re s.str.findall('MONKEY', flags=re.IGNORECASE) 0 [] 1 [Monkey] 2 [] dtype: object

When the pattern matches more than one string in the Series, all matches are returned:

s.str.findall('on') 0 [on] 1 [on] 2 [] dtype: object

Regular expressions are supported too. For instance, the search for all the strings ending with the word ‘on’ is shown next:

s.str.findall('on$') 0 [on] 1 [] 2 [] dtype: object

If the pattern is found more than once in the same string, then a list of multiple strings is returned:

s.str.findall('b') 0 [] 1 [] 2 [b, b] dtype: object