pandas.DataFrame.sum — pandas 3.0.0.dev0+2102.g839747c3f6 documentation (original) (raw)
DataFrame.sum(*, axis=0, skipna=True, numeric_only=False, min_count=0, **kwargs)[source]#
Return the sum of the values over the requested axis.
This is equivalent to the method numpy.sum
.
Parameters:
axis{index (0), columns (1)}
Axis for the function to be applied on. For Series this parameter is unused and defaults to 0.
Warning
The behavior of DataFrame.sum with axis=None
is deprecated, in a future version this will reduce over both axes and return a scalar To retain the old behavior, pass axis=0 (or do not pass axis).
Added in version 2.0.0.
skipnabool, default True
Exclude NA/null values when computing the result.
numeric_onlybool, default False
Include only float, int, boolean columns. Not implemented for Series.
min_countint, default 0
The required number of valid values to perform the operation. If fewer thanmin_count
non-NA values are present the result will be NA.
**kwargs
Additional keyword arguments to be passed to the function.
Returns:
Series or scalar
Sum over requested axis.
See also
Return the sum over Series values.
Return the mean of the values over the requested axis.
Return the median of the values over the requested axis.
Get the mode(s) of each element along the requested axis.
Return the standard deviation of the values over the requested axis.
Examples
idx = pd.MultiIndex.from_arrays( ... [["warm", "warm", "cold", "cold"], ["dog", "falcon", "fish", "spider"]], ... names=["blooded", "animal"], ... ) s = pd.Series([4, 2, 0, 8], name="legs", index=idx) s blooded animal warm dog 4 falcon 2 cold fish 0 spider 8 Name: legs, dtype: int64
By default, the sum of an empty or all-NA Series is 0
.
pd.Series([], dtype="float64").sum() # min_count=0 is the default 0.0
This can be controlled with the min_count
parameter. For example, if you’d like the sum of an empty series to be NaN, pass min_count=1
.
pd.Series([], dtype="float64").sum(min_count=1) nan
Thanks to the skipna
parameter, min_count
handles all-NA and empty series identically.
pd.Series([np.nan]).sum() 0.0
pd.Series([np.nan]).sum(min_count=1) nan