pandas.timedelta_range — pandas 2.2.3 documentation (original) (raw)
pandas.timedelta_range(start=None, end=None, periods=None, freq=None, name=None, closed=None, *, unit=None)[source]#
Return a fixed frequency TimedeltaIndex with day as the default.
Parameters:
startstr or timedelta-like, default None
Left bound for generating timedeltas.
endstr or timedelta-like, default None
Right bound for generating timedeltas.
periodsint, default None
Number of periods to generate.
freqstr, Timedelta, datetime.timedelta, or DateOffset, default ‘D’
Frequency strings can have multiples, e.g. ‘5h’.
namestr, default None
Name of the resulting TimedeltaIndex.
closedstr, default None
Make the interval closed with respect to the given frequency to the ‘left’, ‘right’, or both sides (None).
unitstr, default None
Specify the desired resolution of the result.
Added in version 2.0.0.
Returns:
TimedeltaIndex
Notes
Of the four parameters start
, end
, periods
, and freq
, exactly three must be specified. If freq
is omitted, the resultingTimedeltaIndex
will have periods
linearly spaced elements betweenstart
and end
(closed on both sides).
To learn more about the frequency strings, please see this link.
Examples
pd.timedelta_range(start='1 day', periods=4) TimedeltaIndex(['1 days', '2 days', '3 days', '4 days'], dtype='timedelta64[ns]', freq='D')
The closed
parameter specifies which endpoint is included. The default behavior is to include both endpoints.
pd.timedelta_range(start='1 day', periods=4, closed='right') TimedeltaIndex(['2 days', '3 days', '4 days'], dtype='timedelta64[ns]', freq='D')
The freq
parameter specifies the frequency of the TimedeltaIndex. Only fixed frequencies can be passed, non-fixed frequencies such as ‘M’ (month end) will raise.
pd.timedelta_range(start='1 day', end='2 days', freq='6h') TimedeltaIndex(['1 days 00:00:00', '1 days 06:00:00', '1 days 12:00:00', '1 days 18:00:00', '2 days 00:00:00'], dtype='timedelta64[ns]', freq='6h')
Specify start
, end
, and periods
; the frequency is generated automatically (linearly spaced).
pd.timedelta_range(start='1 day', end='5 days', periods=4) TimedeltaIndex(['1 days 00:00:00', '2 days 08:00:00', '3 days 16:00:00', '5 days 00:00:00'], dtype='timedelta64[ns]', freq=None)
Specify a unit
pd.timedelta_range("1 Day", periods=3, freq="100000D", unit="s") TimedeltaIndex(['1 days', '100001 days', '200001 days'], dtype='timedelta64[s]', freq='100000D')