[basic.lookup.qual.general] (original) (raw)

6 Basics [basic]

6.5 Name lookup [basic.lookup]

6.5.5 Qualified name lookup [basic.lookup.qual]

6.5.5.1 General [basic.lookup.qual.general]

Lookup of an identifierfollowed by a ​::​ scope resolution operator considers only namespaces, types, and templates whose specializations are types.

[Example 1: class A { public: static int n;};int main() { int A; A::n = 42; A b; } template<int> struct B : A {};namespace N { template<int> void B();int f() { return B<0>::n; } } — _end example_]

A qualified name is

• a member-qualified name or
• the terminal name of
  • a qualified-id,
  • a using-declarator,
  • a typename-specifier,
  • a qualified-namespace-specifier, or
  • a nested-name-specifier,elaborated-type-specifier, orclass-or-decltypethat has a nested-name-specifier ([expr.prim.id.qual]).

The lookup context of a member-qualified name is the type of its associated object expression (considered dependent if the object expression is type-dependent).

The lookup context of any other qualified name is the type, template, or namespace nominated by the preceding nested-name-specifier.

[Note 1:

When parsing a class member access, the name following the -> or . is a qualified name even though it is not yet known of which kind.

— _end note_]

[Example 2:

In N::C::m.Base::f() Base is a member-qualified name; the other qualified names are C, m, and f.

— _end example_]

Qualified name lookupin a class, namespace, or enumeration performs a search of the scope associated with it ([class.member.lookup]) except as specified below.

Unless otherwise specified, a qualified name undergoes qualified name lookup in its lookup context from the point where it appears unless the lookup context either is dependent and is not the current instantiation ([temp.dep.type]) or is not a class or class template.

If nothing is found by qualified lookup for a member-qualified name that is the terminal name ([expr.prim.id.unqual]) of a nested-name-specifier and is not dependent, it undergoes unqualified lookup.

[Note 2:

During lookup for a template specialization, no names are dependent.

— _end note_]

[Example 3: int f();struct A { int B, C;template<int> using D = void;using T = void;void f();};using B = A;template<int> using C = A;template<int> using D = A;template<int> using X = A;template<class T> void g(T *p) { p->X<0>::f(); p->template X<0>::f(); p->B::f(); p->template C<0>::f(); p->template D<0>::f(); p->T::f(); } template void g(A*); — _end example_]

If a qualified name Q follows a ~:

• If Q is a member-qualified name, it undergoes unqualified lookup as well as qualified lookup.
• If N has another nested-name-specifier S,Q is looked up as if its lookup context were that nominated by S.
• Otherwise, if the terminal name of N is a member-qualified name M,Q is looked up as if ~Q appeared in place of M (as above).
• Otherwise, Q undergoes unqualified lookup.
• Each lookup for Q considers only types (if Q is not followed by a <) and templates whose specializations are types.
  If it finds nothing or is ambiguous, it is discarded.
• The type-name that is or contains Qshall refer to its (original) lookup context (ignoring cv-qualification) under the interpretation established by at least one (successful) lookup performed.

[Example 4: struct C { typedef int I;};typedef int I1, I2;extern int* p;extern int* q;void f() { p->C::I::~I(); q->I1::~I2(); } struct A { ~A();};typedef A AB;int main() { AB* p; p->AB::~AB(); } — _end example_]