PHP: Hypertext Preprocessor (original) (raw)
ReflectionClass::implementsInterface
(PHP 5, PHP 7, PHP 8)
ReflectionClass::implementsInterface — Implements interface
Description
Parameters
interface
The interface name.
Return Values
Returns [true](reserved.constants.php#constant.true) on success or [false](reserved.constants.php#constant.false) on failure.
Errors/Exceptions
ReflectionClass::implementsInterface() throws anReflectionException if interface is not an interface.
See Also
- ReflectionClass::isInterface() - Checks if the class is an interface
- ReflectionClass::isSubclassOf() - Checks if a subclass
- interface_exists() - Checks if the interface has been defined
- Object Interfaces
Found A Problem?
6 years ago
`Note that this method also returns true when the thing you're reflecting is the interface you're checking for:
implementsInterface('MyInterface')); // bool(true) ?>`
dhairya dot coder at gmail dot com ¶
9 years ago
`//checks that whether class Fruit implements interface apple or not
interface Apple {
function taste();
}
class Fruit implements Apple {
function taste() {
echo "Seet";
}
}
$obj=new ReflectionClass('Fruit');
var_dump($obj->implementsInterface('Apple')); //Here it will checks that whether class Fruit implements interface apple or not
`
keepchen2016 at gmail dot com ¶
7 years ago
`interface Factory
{
public function sayHello();
}
class ParentClass implements Factory
{
public function sayHello()
{
echo "hello\n";
}
}
class ChildrenClass extends ParentClass
{
}
$reflect = new ReflectionClass('ParentClass');
var_dump($reflect->implementsInterface('Factory'));
$second_ref = new ReflectionClass('ChildrenClass');
var_dump($second_ref->isSubclassOf('ParentClass'));
$third_ref = new ReflectionClass('Factory');
var_dump($third_ref->isInterface());
//can not be called as static
var_dump(ReflectionClass::isInterface('Factory'));
die;
//#result
bool(true)
bool(true)
bool(true)
PHP Fatal error: Non-static method ReflectionClass::isInterface() cannot be called statically
`