Function19 (original) (raw)

Apply the body of this function to the arguments.

Apply the body of this function to the arguments.

Attributes

Returns

the result of function application.

Source

Function19.scala

Creates a curried version of this function.

Creates a curried version of this function.

Attributes

Returns

a function f such that f(x1)(x2)(x3)(x4)(x5)(x6)(x7)(x8)(x9)(x10)(x11)(x12)(x13)(x14)(x15)(x16)(x17)(x18)(x19) == apply(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)

Source

Function19.scala

Returns a string representation of the object.

Returns a string representation of the object.

The default representation is platform dependent.

Attributes

Returns

a string representation of the object.

Definition Classes

Source

Function19.scala

Creates a tupled version of this function: instead of 19 arguments, it accepts a single scala.Tuple19 argument.

Creates a tupled version of this function: instead of 19 arguments, it accepts a single scala.Tuple19 argument.

Attributes

Returns

a function f such that f((x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)) == f(Tuple19(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)) == apply(x1, x2, x3, x4, x5, x6, x7, x8, x9, x10, x11, x12, x13, x14, x15, x16, x17, x18, x19)

Source

Function19.scala