algebraic sets and polynomial ideals (original) (raw)
Suppose k is a field. Let 𝔸kn denote affine n-space over k.
For S⊆k[x1,…,xn], define V(S), the zero set of S, by
V(S)={(a1,…,an)∈kn∣f(a1,…,an)=0 for all f∈S} |
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We say that Y⊆𝔸kn is an (affine) algebraic set if there exists T⊆k[x1,…,xn] such that Y=V(T). Taking these subsets of 𝔸kn as a definition of the closed sets of a topology induces the Zariski topology over 𝔸kn.
For Y⊆𝔸kn, define the deal of Y in k[x1,…,xn] by
I(Y)={f∈k[x1,…,xn]∣f(P)=0 for all P∈Y}. |
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It is easily shown that I(Y) is an ideal of k[x1,…,xn].
Thus we have defined a function V mapping from subsets of k[x1,…,xn] to algebraic sets in 𝔸kn, and a function I mapping from subsets of 𝔸n to ideals of k[x1,…,xn].
We remark that the theory of algebraic sets presented herein is most cleanly stated over an algebraically closed field. For example, over such a field, the above have the following properties:
- S1⊆S2⊆k[x1,…,xn] impliesV(S1)⊇V(S2).
- Y1⊆Y2⊆𝔸kn impliesI(Y1)⊇I(Y2).
- For any ideal 𝔞⊂k[x1,…,xn],I(V(𝔞))=Rad(𝔞).
- For any Y⊂𝔸kn, V(I(Y))=Y¯, the closure
of Y in the Zariski topology.
- For any Y⊂𝔸kn, V(I(Y))=Y¯, the closure