std::hypot, std::hypotf, std::hypotl - cppreference.com (original) (raw)

Defined in header
(1)
float hypot ( float x, float y ); double hypot ( double x, double y ); long double hypot ( long double x, long double y ); (since C++11) (until C++23)
/*floating-point-type*/ hypot ( /*floating-point-type*/ x, /*floating-point-type*/ y ); (since C++23) (constexpr since C++26)
float hypotf( float x, float y ); (2) (since C++11) (constexpr since C++26)
long double hypotl( long double x, long double y ); (3) (since C++11) (constexpr since C++26)
(4)
float hypot ( float x, float y, float z ); double hypot ( double x, double y, double z ); long double hypot ( long double x, long double y, long double z ); (since C++17) (until C++23)
/*floating-point-type*/ hypot ( /*floating-point-type*/ x, /*floating-point-type*/ y, /*floating-point-type*/ z ); (since C++23) (constexpr since C++26)
Additional overloads
Defined in header
template< class Arithmetic1, Arithmetic2 > /*common-floating-point-type*/ hypot ( Arithmetic1 x, Arithmetic2 y ); (A) (since C++11) (constexpr since C++26)
template< class Arithmetic1, Arithmetic2, Arithmetic3 > /*common-floating-point-type*/ hypot ( Arithmetic1 x, Arithmetic2 y, Arithmetic3 z ); (B) (since C++17)

1-3) Computes the square root of the sum of the squares of x and y, without undue overflow or underflow at intermediate stages of the computation.The library provides overloads of std::hypot for all cv-unqualified floating-point types as the type of the parameters x and y.(since C++23)

  1. Computes the square root of the sum of the squares of x, y, and z, without undue overflow or underflow at intermediate stages of the computation.The library provides overloads of std::hypot for all cv-unqualified floating-point types as the type of the parameters x, y and z.(since C++23)

A,B) Additional overloads are provided for all other combinations of arithmetic types.

The value computed by the two-argument version of this function is the length of the hypotenuse of a right-angled triangle with sides of length x and y, or the distance of the point (x,y) from the origin (0,0), or the magnitude of a complex number x+_i_y.

The value computed by the three-argument version of this function is the distance of the point (x,y,z) from the origin (0,0,0).

[edit] Parameters

x, y, z - floating-point or integer values

[edit] Return value

1-3,A) If no errors occur, the hypotenuse of a right-angled triangle, \(\scriptsize{\sqrt{x^2+y^2} }\)√x2
+y2
, is returned.

4,B) If no errors occur, the distance from origin in 3D space, \(\scriptsize{\sqrt{x^2+y^2+z^2} }\)√x2
+y2
+z2
, is returned.

If a range error due to overflow occurs, +HUGE_VAL, +HUGE_VALF, or +HUGE_VALL is returned.

If a range error due to underflow occurs, the correct result (after rounding) is returned.

[edit] Error handling

Errors are reported as specified in math_errhandling.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

[edit] Notes

Implementations usually guarantee precision of less than 1 ulp (Unit in the Last Place — Unit of Least Precision): GNU, BSD.

std::hypot(x, y) is equivalent to std::abs(std::complex<double>(x, y)).

POSIX specifies that underflow may only occur when both arguments are subnormal and the correct result is also subnormal (this forbids naive implementations).

Distance between two points (x1, y1, z1) and (x2, y2, z2) on 3D space can be calculated using 3-argument overload of std::hypot as std::hypot(x2 - x1, y2 - y1, z2 - z1). (since C++17)

The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their first argument num1, second argument num2 and the optional third argument num3:

If num1, num2 or num3 has type long double, then std::hypot(num1, num2) has the same effect as std::hypot(static_cast<long double>(num1), static_cast<long double>(num2)), and std::hypot(num1, num2, num3) has the same effect as std::hypot(static_cast<long double>(num1), static_cast<long double>(num2), static_cast<long double>(num3)). Otherwise, if num1, num2 and/or num3 has type double or an integer type, then std::hypot(num1, num2) has the same effect as std::hypot(static_cast<double>(num1), static_cast<double>(num2)), and std::hypot(num1, num2, num3) has the same effect as std::hypot(static_cast<double>(num1), static_cast<double>(num2), static_cast<double>(num3)). Otherwise, if num1, num2 or num3 has type float, then std::hypot(num1, num2) has the same effect as std::hypot(static_cast<float>(num1), static_cast<float>(num2)), and std::hypot(num1, num2, num3) has the same effect as std::hypot(static_cast<float>(num1), static_cast<float>(num2), static_cast<float>(num3)). (until C++23)
If num1, num2 and num3 have arithmetic types, then std::hypot(num1, num2) has the same effect as std::hypot(static_cast</*common-floating-point-type*/>(num1), static_cast</*common-floating-point-type*/>(num2)), and std::hypot(num1, num2, num3) has the same effect as std::hypot(static_cast</*common-floating-point-type*/>(num1), static_cast</*common-floating-point-type*/>(num2), static_cast</*common-floating-point-type*/>(num3)), where /*common-floating-point-type*/ is the floating-point type with the greatest floating-point conversion rank and greatest floating-point conversion subrank among the types of num1, num2 and num3, arguments of integer type are considered to have the same floating-point conversion rank as double.If no such floating-point type with the greatest rank and subrank exists, then overload resolution does not result in a usable candidate from the overloads provided. (since C++23)
Feature-test macro Value Std Feature
__cpp_lib_hypot 201603L (C++17) 3-argument overload of std::hypot (4,B)

[edit] Example

#include #include #include #include #include #include   // #pragma STDC FENV_ACCESS ON   struct Point3D { float x, y, z; };   int main() { // typical usage std::cout << "(1,1) cartesian is (" << std::hypot(1, 1) << ',' << std::atan2(1,1) << ") polar\n";   Point3D a{3.14, 2.71, 9.87}, b{1.14, 5.71, 3.87}; // C++17 has 3-argument hypot overload: std::cout << "distance(a,b) = " << std::hypot(a.x - b.x, a.y - b.y, a.z - b.z) << '\n';   // special values std::cout << "hypot(NAN,INFINITY) = " << std::hypot(NAN, INFINITY) << '\n';   // error handling errno = 0; std::feclearexcept(FE_ALL_EXCEPT); std::cout << "hypot(DBL_MAX,DBL_MAX) = " << std::hypot(DBL_MAX, DBL_MAX) << '\n';   if (errno == ERANGE) std::cout << " errno = ERANGE " << std::strerror(errno) << '\n'; if (std::fetestexcept(FE_OVERFLOW)) std::cout << " FE_OVERFLOW raised\n"; }

Output:

(1,1) cartesian is (1.41421,0.785398) polar distance(a,b) = 7 hypot(NAN,INFINITY) = inf hypot(DBL_MAX,DBL_MAX) = inf errno = ERANGE Numerical result out of range FE_OVERFLOW raised

[edit] See also