[Python-Dev] setcall (original) (raw)
Bj Raz whitequill.bj at gmail.com
Sun Oct 24 18:46:53 CEST 2010
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I was looking for a way to set a function being equal to another function: q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); I was hoping to use something like this: (q).setcall.(m+1) = (q).setcall.(m)+ ((-1)^m) * exp(lnanswer); As a work around. But I have not found the `setcall' built in being there.
Here is the code block I'm working with:
indvar = 200; q = 0; lnanswer = 0; for m = 1:150 lnanswer = (3 * m) * log(indvar) - log(factorial(3 * m)) ; q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); end lnanswer q
Any help would be appreciated. Thank you -------------- next part -------------- An HTML attachment was scrubbed... URL: <http://mail.python.org/pipermail/python-dev/attachments/20101024/3f1e8d62/attachment.html>
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