[Python-Dev] setcall (original) (raw)

Benjamin Peterson benjamin at python.org
Sun Oct 24 18:51:55 CEST 2010

2010/10/24 Bj Raz <whitequill.bj at gmail.com>:

I was looking for a way to set a function being equal to another function: q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); I was hoping to use something like this: (q).setcall.(m+1) = (q).setcall.(m)+ ((-1)^m) * exp(lnanswer); As a work around. But I have not found the `setcall' built in being there.

Here is the code block I'm working with: indvar = 200; q = 0; lnanswer = 0; for m = 1:150 lnanswer = (3 * m) * log(indvar) - log(factorial(3 * m))  ; q(m+1) = q(m)+ ((-1)^m) * exp(lnanswer); end lnanswer q Any help would be appreciated.

Please see python-list. This list is for the development of python.

The SAGE math package can do something like this.

-- Regards, Benjamin

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