Nonconstant Index into varargin or varargout in a for-Loop - MATLAB & Simulink (original) (raw)

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Issue

Your MATLABĀ® code contains a for-loop that indexes intovarargin or varargout. When you generate code, you see this error message:

Non-constant expression or empty matrix. This expression must be constant because its value determines the size or class of some expression.

Cause

At code generation time, the code generator must be able to determine the value of an index into varargin or varagout. Whenvarargin or varagout are indexed in afor-loop, the code generator determines the index value for each loop iteration by unrolling the loop. Loop unrolling makes a copy of the loop body for each loop iteration. In each iteration, the code generator determines the value of the index from the loop counter.

The code generator is unable to determine the value of an index intovarargin or varagout when:

Solution

Use one of these solutions:

Force Loop Unrolling

Force loop unrolling by using coder.unroll. For example:

function [x,y,z] = fcn(a,b,c) %#codegen [x,y,z] = subfcn(a,b,c);

function varargout = subfcn(varargin) j = 0;

coder.unroll(); for i = 1:nargin j = j + 1; varargout{j} = varargin{j}; end

Rewrite the Code

Rewrite the code so that the code generator can detect the relationship between the index and the loop counter. For example:

function [x,y,z] = fcn(a,b,c) %#codegen [x,y,z] = subfcn(a,b,c);

function varargout = subfcn(varargin) for i = 1:nargin varargout{i} = varargin{i}; end

See Also

coder.unroll