Titchmarsh Theorem (original) (raw)
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If is square integrable over the real
-axis, then any one of the following implies the other two:
1. The Fourier transform is 0 for
.
2. Replacing by
, the function
is analytic in the complex plane
for
and approaches
almost everywhere as
. Furthermore,
for some number
and
(i.e., the integral is bounded).
3. The real and imaginary parts of are Hilbert transforms of each other
(Bracewell 1999, Problem 8, p. 273).
See also
Fourier Transform, Hilbert Transform
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References
Bracewell, R. The Fourier Transform and Its Applications, 3rd ed. New York: McGraw-Hill, 1999.
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Cite this as:
Weisstein, Eric W. "Titchmarsh Theorem." From MathWorld--A Wolfram Resource. https://mathworld.wolfram.com/TitchmarshTheorem.html