numpy.inner — NumPy v2.2 Manual (original) (raw)
numpy.inner(a, b, /)#
Inner product of two arrays.
Ordinary inner product of vectors for 1-D arrays (without complex conjugation), in higher dimensions a sum product over the last axes.
Parameters:
a, barray_like
If a and b are nonscalar, their last dimensions must match.
Returns:
outndarray
If a and b are both scalars or both 1-D arrays then a scalar is returned; otherwise an array is returned.out.shape = (*a.shape[:-1], *b.shape[:-1])
Raises:
ValueError
If both a and b are nonscalar and their last dimensions have different sizes.
See also
Sum products over arbitrary axes.
Generalised matrix product, using second last dimension of b.
Vector dot product of two arrays.
Einstein summation convention.
Notes
For vectors (1-D arrays) it computes the ordinary inner-product:
np.inner(a, b) = sum(a[:]*b[:])
More generally, if ndim(a) = r > 0
and ndim(b) = s > 0
:
np.inner(a, b) = np.tensordot(a, b, axes=(-1,-1))
or explicitly:
np.inner(a, b)[i0,...,ir-2,j0,...,js-2] = sum(a[i0,...,ir-2,:]*b[j0,...,js-2,:])
In addition a or b may be scalars, in which case:
Examples
Ordinary inner product for vectors:
import numpy as np a = np.array([1,2,3]) b = np.array([0,1,0]) np.inner(a, b) 2
Some multidimensional examples:
a = np.arange(24).reshape((2,3,4)) b = np.arange(4) c = np.inner(a, b) c.shape (2, 3) c array([[ 14, 38, 62], [ 86, 110, 134]])
a = np.arange(2).reshape((1,1,2)) b = np.arange(6).reshape((3,2)) c = np.inner(a, b) c.shape (1, 1, 3) c array([[[1, 3, 5]]])
An example where b is a scalar:
np.inner(np.eye(2), 7) array([[7., 0.], [0., 7.]])