tf.compat.v1.math.minimum | TensorFlow v2.16.1 (original) (raw)
Returns the min of x and y (i.e. x < y ? x : y) element-wise.
tf.compat.v1.math.minimum(
x: Annotated[Any, tf.raw_ops.Any],
y: Annotated[Any, tf.raw_ops.Any],
name=None
) -> Annotated[Any, tf.raw_ops.Any]
Both inputs are number-type tensors (except complex). minimum expects that both tensors have the same dtype.
Examples:
x = tf.constant([0., 0., 0., 0.])
y = tf.constant([-5., -2., 0., 3.])
tf.math.minimum(x, y)
<tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -2., 0., 0.], dtype=float32)>
Note that minimum supports broadcast semantics for x and y.
x = tf.constant([-5., 0., 0., 0.])
y = tf.constant([-3.])
tf.math.minimum(x, y)
<tf.Tensor: shape=(4,), dtype=float32, numpy=array([-5., -3., -3., -3.], dtype=float32)>
The reduction version of this elementwise operation is tf.math.reduce_min
| Args | |
|---|---|
| x | A Tensor. Must be one of the following types: bfloat16, half, float32, float64, int8, uint8, int16, uint16, int32, uint32, int64, uint64. |
| y | A Tensor. Must have the same type as x. |
| name | A name for the operation (optional). |
| Returns |
|---|
| A Tensor. Has the same type as x. |