Surface Area of a Cylinder (original) (raw)

Last Updated : 24 Mar, 2026

The surface area of a cylinder is the total area occupied by all its outer surfaces, including the curved surface and the two circular bases. It represents the complete exterior covering of the cylinder and is measured in square units.

The surface area of a cylinder is divided into two components:

**Curved Surface Area of a Cylinder (CSA)

The curved surface area (CSA) is the area covered by its curved outer surface, excluding the top and bottom circular bases. It represents the lateral covering of the cylinder.

For a cylinder with radius _r and height _h:

Curved Surface Area (CSA) = 2πrh square units

where

Total Surface Area of a Cylinder (TSA)

The total surface area is the sum of the areas of its two circular bases and its curved surface. It represents the complete outer covering of the cylinder.

surface

The above figure shows how a cylinder can be opened into a rectangle along with two circular bases.

For a cylinder with radius _r and height _h:

Total Surface Area (T.S.A) = 2πrh + 2πr2 = 2πr(h+r) square units.

Where,

**Example: Find the total surface area of a cylinder with radius 5 cm and height 8 cm.

**Solution:

TSA = 2πr(r + h)
= 2 × 3.14 × 5 × (5 + 8)
= 408.4 cm² (approx.)

Sample Problems

**Problem 1: Compute the total surface area of the cylinder with a radius of 5 cm and a height of 10 cm.

**Solution:

Since, we know,

Total surface area of a cylinder, A = 2πr(r+h) square units

Therefore, A = 2π × 5(5 + 10) = 2π × 5(15)

= 2π × 75 = 150 × 3.14

= 471 cm2

**Problem 2: A cylinder has a radius of 7 cm and a height of 20 cm. A thin sheet is used to cover the entire outer surface of the cylinder. Find the total surface area required.

**Solution:

Given: r = 7 cm, h = 20 cm

TSA = 2πr(r + h)
= 2 × (22/7) × 7 × (7 + 20)
= 2 × 22 × 27
= 1188 cm²

**Problem 3: A cylindrical pipe has an inner radius of 5 cm and a height of 28 cm. Only the outer curved surface is to be painted. Find the curved surface area to be painted.

**Solution:

Given: r = 5 cm, h = 28 cm

CSA = 2πrh
= 2 × (22/7) × 5 × 28
= 2 × 22 × 5 × 4
= 880 cm²

**Problem 4: A water tank has a radius of 40 inches and a height of 150 inches. Find the area.

**Solution:

Water tank is cylindrical in nature.

Total Surface Area of a cylinder is given by, 2πr(h+r)

TSA = 2 × 22/7 × 40(150 + 40)

TSA = 2 × 22/7 × 40 × 190

TSA = 440/7 × 7600

TSA = 3344000/ 7

Area = 47,7142.857 sq.inches.

**Problem 5: The height of a cylinder is twice its radius. If the radius is 6 cm, find the total surface area of the cylinder.

**Solution:

Given: r = 6 cm, h = 2r = 12 cm

TSA = 2πr(r + h)
= 2 × 3.14 × 6 × (6 + 12)
= 2 × 3.14 × 6 × 18
= 2 × 3.14 × 108
= 678.24 cm²