Symmetric and Skew Symmetric Matrices (original) (raw)

Last Updated : 18 Nov, 2025

Symmetric and Skew Symmetric Matrices are types of square matrices based on the relation between a matrix and its transpose. These matrices are one of the most used matrices out of all the matrices out there.

Symmetric matrices have use cases in optimization, physics, and statistics, whereas skew-symmetric matrices are used in subjects such as mechanics and electromagnetism.

Symmetric Matrix

If for a matrix, the transposed form of that matrix is the same as the original matrix, then that matrix is said to be a Symmetric Matrix. Let, a square matrix A of size **n x n is said to be symmetric if

At = A

Where,

So, [aji] represents the transpose of [aij] matrix.

**For example, let us consider a square matrix A = \begin{bmatrix} 3 & 4 \\ 4 & 5 \end{bmatrix}, and A^T \ = \ \begin{bmatrix} 3 & 4 \\ 4 & 5 \end{bmatrix}

So, this matrix is a Symmetric Matrix, because the transposed form of this matrix is itself the original matrix.

Properties of Symmetric Matrices

Some Properties of Symmetric Matrices are as follows:

**Property: If matrix A is a square matrix then (A + At) is always symmetric.

**Prove: To find if a matrix symmetric or not, first, we have to find the transposed form of the given matrix

So, let's find the transpose of (A + At)
= (_A + _A t)_t
= _A t + (_A t)_t
= _A t + _A [_here, (_A t)_t = __A_]
= (_A + _A t)

So, this is the same as the given matrix, so it is symmetric.

Skew Symmetric Matrix

If for a matrix, the transposed form of that matrix is the same as the negative of the original matrix, then that matrix is said to be a Skew-Symmetric Matrix. Let, a square matrix A of size n x n is said to be skew-symmetric if

At = -A

Where,

For Example, consider A = \begin{pmatrix} 0 & -2 & 3 \\ 2 & 0 & -4 \\ -3 & 4 & 0 \end{pmatrix}, and A^T = \begin{pmatrix} 0 & 2 & -3 \\ -2 & 0 & 4 \\ 3 & -4 & 0 \end{pmatrix}

Here, in the transposed form the matrix looks like the negative of the original matrix.

Properties of Skew-Symmetric Matrices

There are some rules that come from the concept of Symmetric and Skew-Symmetric Matrices,

**Property: If matrix A is a square matrix then (A - At) is always skew-symmetric.

**Proof: To find if a matrix skew-symmetric or not, first, we have to find the transposed form of the given matrix

So, let's find the transpose of (A - At)

= (_A − _A t)_t
= _A t − (_A t)_t
= _A t − _A [_here, (_A t)__t_= __A_]
= − (_A − _A t)

So, this form is the negative of the given matrix, so it is skew-symmetric.

Determinant of Skew Symmetric Matrix

Skew-Symmetric Matrix, is a square matrix and the **determinant of the Skew-Symmetric matrices follows the condition discussed below. If we have a Skew-Symmetric Matrix then,

det (AT) = det (-A) = (-1)n det(A)

Also, every skew-symmetric matrix of odd order is a **singular matrix, i.e. its determinant is zero and hence its determinant does not exist.

Eigenvalue of Skew Symmetric Matrix

The eigenvalues of a skew-symmetric matrix are zero. It is a real matrix, but the matrix can have non-real eigenvalues. Also, we can easily express every square matrix in the form of the sum of a symmetric and a skew-symmetric matrix, uniquely.

Matrix Decomposition: Symmetric and Skew-Symmetric Matrices

**Property: Every square matrix can be expressed uniquely as the sum of symmetric and skew-symmetric matrices.

**Proof:

Let A be a square matrix,

We can write, A = A/2 + A/2

= \frac{1}{2}(A+A^t) + \frac{1}{2}(A-A^t)

Let, A = P + Q

Where, \quad P=\frac{1}{2}(A+A^t) ,\quad Q=\frac{1}{2}(A-A^t)

Now, find **P t and **Q t [Pt is the **transpose of P]

P^t =(\frac{1}{2}(A+A^t))^t \\ =\frac{1}{2}(A+A^t)^t \\ =\frac{1}{2}(A^t+(A^t)^t) \\ =\frac{1}{2}(A+A^t) \\ = P

and,

Q^t =(\frac{1}{2}(A-A^t))^t \\ =\frac{1}{2}(A-A^t)^t \\ =\frac{1}{2}(A^t-(A^t)^t) \\ =\frac{1}{2}(A^t-A) \\ =-\frac{1}{2}(A-A^t) \\ = -Q

So, here P is symmetric and Q is skew-symmetric matrices and A is the sum of P and Q.

**Example: Express matrix A as the sum of a symmetric and skew-symmetric matrix, Where

\bold{A = \begin{bmatrix} 0 & a & b \\ -a & 0 & c \\ -b & -c & 0 \end{bmatrix} }

**Answer:

First, find the transpose of A

A^T = \begin{bmatrix} 0 & -a & -b \\ a & 0 & -c \\ b & c & 0 \end{bmatrix}

Now find (A + At) and (A - At)

(A+A^T) \\ =\begin{bmatrix} 0 & a & b \\ -a & 0 & c \\ -b & -c & 0 \end{bmatrix} + \begin{bmatrix} 0 & -a & -b \\ a & 0 & -c \\ b & c & 0 \end{bmatrix} \\ =\begin{bmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{bmatrix} \\ \therefore \frac{1}{2}(A+A^T) \\ = \frac{1}{2}\begin{bmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{bmatrix} \\ = \begin{bmatrix} 0 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{bmatrix}

Similarly:

(A-A^T) \\ =\begin{bmatrix} 0 & a & b \\ -a & 0 & c \\ -b & -c & 0 \end{bmatrix} - \begin{bmatrix} 0 & -a & -b \\ a & 0 & -c \\ b & c & 0 \end{bmatrix} \\ =\begin{bmatrix} 0 & 2a & 2b \\ -2a & 0 & 2c \\ -2b & -2c & 0 \end{bmatrix} \\ \therefore \frac{1}{2}(A-A^T) \\ = \frac{1}{2}\begin{bmatrix} 0 & 2a & 2b \\ -2a & 0 & 2c \\ -2b & -2c & 0 \end{bmatrix} \\ = \begin{bmatrix} 0 & a & b \\ -a & 0 & c \\ -b & -c & 0 \end{bmatrix} =A

Conclusion

A=\frac{1}{2}(A+A^T)+\frac{1}{2}(A-A^T)

A = symmetric part + skew-symmetric part

A = 0 + A

Symmetric vs Skew Symmetric Matrices

There are some key differences between Symmetric and Skew Symmetric Matrices, which are as follows:

Symmetric Matrix Skew-Symmetric Matrix
A matrix A such that AT = A A matrix A such that AT = -A.
Contains real numbers Diagonal entries are always zero
Same value as a corresponding entry on the opposite side of diagonal Opposite sign as a corresponding entry on the opposite side of diagonal
All eigenvalues are real Eigenvalues come in imaginary pairs
\begin{bmatrix}1&2&3\\2&4&5\\3&5&6 \end{bmatrix} \begin{bmatrix}0&1&-2\\-1&0&3\\2&-3&0 \end{bmatrix}

Sample Problems on Symmetric and Skew Symmetric Matrices

**Problem 1: Check whether the following matrix is symmetric or skew-symmetric.

\bold{A = \begin{bmatrix} 2 & 5 & 8 \\ 5 & 1 & 7 \\ 8 & 7 & 4 \end{bmatrix}}

**Solution:

As A = \begin{bmatrix} 2 & 5 & 8 \\ 5 & 1 & 7 \\ 8 & 7 & 4 \end{bmatrix}

and A^T = \begin{bmatrix} 2 & 5 & 8 \\ 5 & 1 & 7 \\ 8 & 7 & 4 \end{bmatrix} = A

Thus, the given matrix is symmetric matrix.

**Problem 2: Is the following matrix symmetric?

\bold{A = \begin{bmatrix} 5 & 2 & 1 \\ 2 & 3 & 4 \\ 1 & 4 & 6 \end{bmatrix}}

**Solution:

As A = \begin{bmatrix} 5 & 2 & 1 \\ 2 & 3 & 4 \\ 1 & 4 & 6 \end{bmatrix}

and Transpose of matrix A i.e., A^T = \begin{bmatrix} 5 & 2 & 1 \\ 2 & 3 & 4 \\ 1 & 4 & 6 \end{bmatrix} = A

Thus, the given matrices is symmetric matrix.

**Problem 3: Check whether the following matrix is symmetric or skew-symmetric.

\bold{A = \begin{bmatrix} 0 & 4 & -7 \\ -4 & 0 & -3 \\ 7 & 3 & 0 \end{bmatrix}}

**Solution:

As A = \begin{bmatrix} 0 & 4 & -7 \\ -4 & 0 & -3 \\ 7 & 3 & 0 \end{bmatrix}

and A^T = \begin{bmatrix} 0 & -4 & 7 \\ 4 & 0 & 3 \\ -7 & -3 & 0 \end{bmatrix} = -A

Thus, A given matrix is skew-symmetric matrix.

**Problem 4: What type of matrices is the following matrix: symmetric or skew-symmetric?

\bold{A = \begin{bmatrix} 0 & 3 & -7 \\ -3 & 0 & 2 \\ 7 & -2 & 0 \end{bmatrix}}

**Solution:

As A = \begin{bmatrix} 0 & 3 & -7 \\ -3 & 0 & 2 \\ 7 & -2 & 0 \end{bmatrix}

and A^T = \begin{bmatrix} 0 & -3 & 7 \\ 3 & 0 & -2 \\ -7 & 2 & 0 \end{bmatrix} = -A

Thus, A given matrix is a skew-symmetric matrix.