tf.linalg.lu_solve | TensorFlow v2.16.1 (original) (raw)
tf.linalg.lu_solve
Stay organized with collections Save and categorize content based on your preferences.
Solves systems of linear eqns A X = RHS
, given LU factorizations.
View aliases
Compat aliases for migration
SeeMigration guide for more details.
tf.linalg.lu_solve(
lower_upper, perm, rhs, validate_args=False, name=None
)
Args | |
---|---|
lower_upper | lu as returned by tf.linalg.lu, i.e., if matmul(P, matmul(L, U)) = X then lower_upper = L + U - eye. |
perm | p as returned by tf.linag.lu, i.e., if matmul(P, matmul(L, U)) = X then perm = argmax(P). |
rhs | Matrix-shaped float Tensor representing targets for which to solve;A X = RHS. To handle vector cases, use: lu_solve(..., rhs[..., tf.newaxis])[..., 0]. |
validate_args | Python bool indicating whether arguments should be checked for correctness. Note: this function does not verify the implied matrix is actually invertible, even when validate_args=True. Default value: False (i.e., don't validate arguments). |
name | Python str name given to ops managed by this object. Default value: None (i.e., 'lu_solve'). |
Returns | |
---|---|
x | The X in A @ X = RHS. |
Examples
import numpy as np
import tensorflow as tf
import tensorflow_probability as tfp
x = [[[1., 2],
[3, 4]],
[[7, 8],
[3, 4]]]
inv_x = tf.linalg.lu_solve(*tf.linalg.lu(x), rhs=tf.eye(2))
tf.assert_near(tf.matrix_inverse(x), inv_x)
# ==> True
Except as otherwise noted, the content of this page is licensed under the Creative Commons Attribution 4.0 License, and code samples are licensed under the Apache 2.0 License. For details, see the Google Developers Site Policies. Java is a registered trademark of Oracle and/or its affiliates. Some content is licensed under the numpy license.
Last updated 2024-04-26 UTC.