tf.math.is_non_decreasing  |  TensorFlow v2.16.1 (original) (raw)

Returns True if x is non-decreasing.

View aliases

Compat aliases for migration

SeeMigration guide for more details.

tf.compat.v1.debugging.is_non_decreasing, tf.compat.v1.is_non_decreasing, tf.compat.v1.math.is_non_decreasing

tf.math.is_non_decreasing(
    x, name=None
)

Elements of x are compared in row-major order. The tensor [x[0],...]is non-decreasing if for every adjacent pair we have x[i] <= x[i+1]. If x has less than two elements, it is trivially non-decreasing.

See also: is_strictly_increasing

x1 = tf.constant([1.0, 1.0, 3.0]) tf.math.is_non_decreasing(x1) <tf.Tensor: shape=(), dtype=bool, numpy=True> x2 = tf.constant([3.0, 1.0, 2.0]) tf.math.is_non_decreasing(x2) <tf.Tensor: shape=(), dtype=bool, numpy=False>